ES6 equivalent of Node.js require function call [duplicate]

Question

What's the shortest ES6 equivalent of require function call below?

module.exports = function(app) {...};

require('./routes')(app);

In other words is there a one-liner equivalent in ES6 modules?

Answer 1

I've just started to delve into ES6, but I believe that would be something like:

import * as routes from './routes';

...assuming ./routes is an ES6 module exporting something.

This can then be used immediately like so:

import * as routes from './routes';

doAThing( routes.myVar, routes.myMethod() );

If the module has only a single named export, it's still two lines to import, then call:

import { name } from './routes';
name();

This is the same for any number of exports:

import { name1, name2 } from './routes';
name1();
name2();

A better import is as written above:

import * as routes from './routes';
routes.foo();
routes.bar();

I used the "recommended" format from this Axel Rauschmayer post relating to ES6 modules, but depending on what the module exports your import statement may look different:

import * as fs from 'fs'; // recommended

I find this (1 line to import, 1 line to invoke) syntax clear and readable, so I like it. For some, it may seem unfortunate. However, the bottom line is that there is no one line import/invoke in ES6