ES6 Deconstructing an array of objects

Question

I have this object

const config = {
    js: {
        files: [
            {
                src: './js/app.js',
                name: 'script.js',
                dest: 'public_html/js/'
            },
            {
                src: './js/admin.js',
                name: 'script.js',
                dest: 'public_html/js/'
            }
        ]
    }
};

and I want to get this (getting all the sources):

sources = ['./js/app.js', './js/admin.js']

// or, at least
sources = [{'./js/app.js'}]

I know how to do it with a loop, but can I do it with ES6 deconstructing?

Something like:

{sources = [{src}]} = config.js;

OR

{[{src}] : sources} = config.js;

Answer 1

Destructuring is not meant for a case such as this. Simply using map() will easily get the job done.

const config = {
    js: {
        files: [
            {
                src: './js/app.js',
                name: 'script.js',
                dest: 'public_html/js/'
            },
            {
                src: './js/admin.js',
                name: 'script.js',
                dest: 'public_html/js/'
            }
        ]
    }
};

console.log(config.js.files.map(x => x.src));

Answer 2

You could use destructuring with an iterator like Array#entries and a for ... of statement and a temporary variable index.

var config = { js: { files: [{ src: './js/app.js', name: 'script.js', dest: 'public_html/js/' }, { src: './js/admin.js', name: 'script.js', dest: 'public_html/js/' }] } },
    index,
    result = [];

for ({ 0: index, 1: { src: result[index] } } of config.js.files.entries());

console.log(result)