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I have an Array const arr = new Array(100).
And I set
arr[0] = 'A'
arr[49] = 'X'
When destructuring the 1st element, I can do it like:
let [first] = arr
How the statement would be like if I want to access to the 50th element by destructuring expression?
306
Destructuring in Arrays. To destructure an array in JavaScript, we use the square brackets [] to store the variable name which will be assigned to the name of the array storing the element. const [var1, var2, ...]
Destructuring takes each variable on the array on the left-hand side and maps it to the element at the same index in the animals array. When we write out firstElement , we are saying we want to get access to the first element in the animals array and assign it to the variable of firstElement.
Destructuring means to break down a complex structure into simpler parts. With the syntax of destructuring, you can extract smaller fragments from objects and arrays. It can be used for assignments and declaration of a variable.
Similarly, to destructure arrays to multiple variables, use the square brackets [ ] instead of curly brackets. Arrays: const [variable1,variable2] = arrayName; Note: In the case of destructuring objects, the name of the variables should be the same as the name of the properties of the object.
You can grab the element using object destructuring, like so:
const arr = Array(50).fill(0).map((_, i) => `Element ${i + 1}`)
const {49: fifty} = arr
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