Menu
HTML CODE
<!DOCTYPE html>
<html>
<head>
<style>
#right
{
margin-top:109px;
margin-right:225px;
}
#button
{
margin-right:;
margin-top:22px;
}
</style>
</head>
<body>
<div id="total" style="width:1350px">
<div id="top" style="width:1350px;height:69px;background-image:url('top.png');float:;"></div>
<div id="body" style="width:1350px;height:570px;background-image:url('body.jpg');float:;">
<div id="right" style="background-color:;height:283px;width:320px;float:right;">
<form action="new.php" method="post" >
<input type="text" name="username" value="" size="37" placeholder="username"style="height:20px"><br><br>
<pre><input type="password" name="password" value="" size="37" placeholder="password"style="height:20px">
<div id="button"><input type="image" name="" value="submit" src="button.png" /> <input type="checkbox" value="check"><br></pre>
</div>
</form>
</div>
</div>
<div id="footer" style="width:1350px;height:33px;background-image:url('footer.png');clear:both;"></div>
</div>
</body>
</html>
MY PHP CODE
<?php
$con=mysqli_connect("localhost","prabha","prabha","prabha");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="INSERT INTO table (username, password)
VALUES
('$_POST[username]','$_POST[password]')";
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
echo "1 record added";
mysqli_close($con);
?>
When i clicked on submit button after entering username:prabha password:passwordofprabha
It shows the following error. Please fix my code.
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'table (username, password) VALUES ('prabha','passwordofprabha')' at line 1
248
Use ` backticks for MYSQL reserved words...
table name "table" is reserved word for MYSQL...
so your query should be as follows...
$sql="INSERT INTO `table` (`username`, `password`)
VALUES
('$_POST[username]','$_POST[password]')";
Some special characters give this type of error, so use
$query="INSERT INTO `tablename` (`name`, `email`)
VALUES
('$_POST[name]','$_POST[email]')";
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