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Error in 'SqlQuery' method is not natively supported by your database provider

In function execution calls of dbContext.Database.SqlQuery<T> the following exception:

'The element type 'MyEntity' used in 'SqlQuery' method is not natively supported by your database provider. Either use a supported element type, or use ModelConfigurationBuilder.DefaultTypeMapping to define a mapping for your type.'

Exception details

The source code.

using Microsoft.EntityFrameworkCore;
using Microsoft.EntityFrameworkCore.Metadata.Builders;

namespace Test
{
    public class Employee
    {
        public int Id { get; set; }
        public string FirstName { get; set; }
        public string LastName { get; set; }
    }
    public class EmployeeInfo
    {
        public int EmployeeId { get; set; }
        public string Name { get; set; }
    }

    public class EmployeeDBContext : DbContext
    {
        public DbSet<Employee> Employees { get; set; }
        public EmployeeDBContext() { }
        public EmployeeDBContext(DbContextOptions<EmployeeDBContext> options)
            : base(options) { }

        protected override void ConfigureConventions(ModelConfigurationBuilder configurationBuilder)
        {
            base.ConfigureConventions(configurationBuilder);

            //Action<TypeMappingConfigurationBuilder<EmployeeInfo>> actionEmployeeInfo = (buildAction) => { };
            //configurationBuilder.DefaultTypeMapping(actionEmployeeInfo);
            //Action<TypeMappingConfigurationBuilder> action = (buildAction) => { };
            //configurationBuilder.DefaultTypeMapping(typeof(EmployeeInfo), action);
            //configurationBuilder.DefaultTypeMapping(typeof(EmployeeInfo));
            configurationBuilder.DefaultTypeMapping<EmployeeInfo>();
        }

        protected override void OnConfiguring(DbContextOptionsBuilder optionsBuilder)
        {
            optionsBuilder.UseSqlServer("Data source=localhost;Database=EmployeeDB;User Id=sa;Password=Dev.NET;");
        }

        protected override void OnModelCreating(ModelBuilder modelBuilder)
        {
            base.OnModelCreating(modelBuilder);
            modelBuilder.Entity<Employee>(builder => builder.HasKey(x => x.Id));
        }
    }
}

The Test code.

using FluentAssertions;
using Microsoft.EntityFrameworkCore;
using NUnit.Framework;

namespace Test
{
    [TestFixture]
    public class EmployeeTest
    {
        [Test(Description = nameof(Find_Employee_ReturnModel))]
        public void Find_Employee_ReturnModel()
        {
            // Arrange
            var dbContext = new EmployeeDBContext();
            dbContext.Database.EnsureDeleted();
            dbContext!.Database.EnsureCreated();

            var employee = new Employee { FirstName = "Joao", LastName = "Gomes" };
            dbContext.Employees.Add(employee);
            dbContext.SaveChanges();

            // Act
            var employeeInfo = dbContext.Database.SqlQuery<EmployeeInfo>($"SELECT e.Id as EmployeeId, e.FirstName as Name FROM Employee e").ToList();

            // Assert
            employeeInfo.Should().HaveCount(1);
        }
    }
}

Added recommended settings to return a type that is not natively supported by the database provider.

DefaultTypeMapping

protected override void ConfigureConventions(ModelConfigurationBuilder configurationBuilder)
        {
            base.ConfigureConventions(configurationBuilder);

            //Action<TypeMappingConfigurationBuilder<EmployeeInfo>> actionEmployeeInfo = (buildAction) => { };
            //configurationBuilder.DefaultTypeMapping(actionEmployeeInfo);
            //Action<TypeMappingConfigurationBuilder> action = (buildAction) => { };
            //configurationBuilder.DefaultTypeMapping(typeof(EmployeeInfo), action);
            //configurationBuilder.DefaultTypeMapping(typeof(EmployeeInfo));
            configurationBuilder.DefaultTypeMapping<EmployeeInfo>();
        }
like image 756
Thiago Guislotti Avatar asked Feb 24 '26 03:02

Thiago Guislotti


1 Answers

Not exactly a solution but a workaround until EF8 comes:

statement += " for json path";
var asJson = string.Join("", _context.Database.SqlQueryRaw<string>(statement)); 
return System.Text.Json.JsonSerializer.Deserialize<TModel[]>(asJson);
like image 175
krizzzn Avatar answered Feb 26 '26 17:02

krizzzn



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