please refer to the notebook at the following address
LogisticRegression
this portion of code,
scores = cross_val_score(LogisticRegression(), X, y, scoring='accuracy', cv=10)
print scores
print scores.mean()
generates the following error in a window 7 64bit machine
---------------------------------------------------------------------------
IndexError Traceback (most recent call last)
<ipython-input-37-4a10affe67c7> in <module>()
1 # evaluate the model using 10-fold cross-validation
----> 2 scores = cross_val_score(LogisticRegression(), X, y, scoring='accuracy', cv=10)
3 print scores
4 print scores.mean()
C:\Python27\lib\site-packages\sklearn\cross_validation.pyc in cross_val_score(estimator, X, y, scoring, cv, n_jobs, verbose, fit_params, score_func, pre_dispatch)
1140 allow_nans=True, allow_nd=True)
1141
-> 1142 cv = _check_cv(cv, X, y, classifier=is_classifier(estimator))
1143 scorer = check_scoring(estimator, score_func=score_func, scoring=scoring)
1144 # We clone the estimator to make sure that all the folds are
C:\Python27\lib\site-packages\sklearn\cross_validation.pyc in _check_cv(cv, X, y, classifier, warn_mask)
1366 if classifier:
1367 if type_of_target(y) in ['binary', 'multiclass']:
-> 1368 cv = StratifiedKFold(y, cv, indices=needs_indices)
1369 else:
1370 cv = KFold(_num_samples(y), cv, indices=needs_indices)
C:\Python27\lib\site-packages\sklearn\cross_validation.pyc in __init__(self, y, n_folds, indices, shuffle, random_state)
428 for test_fold_idx, per_label_splits in enumerate(zip(*per_label_cvs)):
429 for label, (_, test_split) in zip(unique_labels, per_label_splits):
--> 430 label_test_folds = test_folds[y == label]
431 # the test split can be too big because we used
432 # KFold(max(c, self.n_folds), self.n_folds) instead of
IndexError: too many indices for array
I am using scikit.learn 0.15.2, it is suggested here that may a specific problem for windows 7, 64 bit machine.
==============update==============
I found the following code actually works
from sklearn.cross_validation import KFold
cv = KFold(X.shape[0], 10, shuffle=True, random_state=33)
scores = cross_val_score(LogisticRegression(), X, y, scoring='accuracy', cv=cv)
print scores
==============update 2=============
it seems due to some package update, I can no longer reproduce such error on my machine. If you are facing the same issue on a windows 7 64bit machine, please let me know.
I had the same error you got and was looking for answers when I found this question.
I used the same sklearn.cross_validation.cross_val_score (except different algorithm) and the same machine windows 7, 64 bit.
I tried your solution from above and it "worked", but it gave me the following warning:
C:\Users\E245713\AppData\Local\Continuum\Anaconda3\lib\site-packages\sklearn\cross_validation.py:1531: DataConversionWarning: A column-vector y was passed when a 1d array was expected. Please change the shape of y to (n_samples, ), for example using ravel(). estimator.fit(X_train, y_train, **fit_params)
After reading the warning, I figured that the problem has something to do with the shape of 'y' (my label column). The keyword to try from the warning is "ravel()". So, I tried the following:
y_arr = pd.DataFrame.as_matrix(label)
print(y_arr)
print(y_arr.shape())
which gave me
[[1]
[0]
[1]
..,
[0]
[0]
[1]]
(87939, 1)
When I added 'ravel()':
y_arr = pd.DataFrame.as_matrix(label).ravel()
print(y_arr)
print(y_arr.shape())
it gave me:
[1 0 1 ..., 0 0 1]
(87939,)
The dimension of 'y_arr' has to be in the form of (87939,) not (87939,1). After that my original cross_val_score worked without adding the Kfold code.
Hope this helps.
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