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error: "CSRF verification failed. Request aborted." when using jquery ajax with Django

in template:

<script type="text/javascript">
        $.ajax({
             type:"POST",
             url:"{% url DrHub.views.ajxTest %}",
             data: {
                    'start': $('#id_startTime').val(),
                    'end': $('#id_endTime').val(),
                    'csrfmiddlewaretoken': '{{ csrf_token }}'
             },
             success: function(data){
                 alert(data);
             }
        });
</script>
.
.
.
<form method='POST' action=".">
    {% csrf_token %}
    <input type="text id="id_startTime" />
    <input type="text id="id_endTime" />
    <input type="submit" value="send" />
</form>

in views:

def ajxTest(request):
   if request.is_ajax():
      if request.method == 'POST':
         return HttpResponse(json.dumps({'message' : 'awesome'},ensure_ascii=False), mimetype='application/javascript')

in settings.py:

MIDDLEWARE_CLASSES = (
    'django.middleware.common.CommonMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    'django.middleware.locale.LocaleMiddleware',
)

when submitting form I have this error:CSRF verification failed. Request aborted.

I searched alot but none of suggested solutions worked for me!

like : Django CSRF check failing with an Ajax POST request

and : Ajax Post in Django framework?

I refreenced to a js file with this content:

$.ajaxSetup({ 
     beforeSend: function(xhr, settings) {
         function getCookie(name) {
             var cookieValue = null;
             if (document.cookie && document.cookie != '') {
                 var cookies = document.cookie.split(';');
                 for (var i = 0; i < cookies.length; i++) {
                     var cookie = jQuery.trim(cookies[i]);
                     // Does this cookie string begin with the name we want?
                 if (cookie.substring(0, name.length + 1) == (name + '=')) {
                     cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
                     break;
                 }
             }
         }
         return cookieValue;
         }
         if (!(/^http:.*/.test(settings.url) || /^https:.*/.test(settings.url))) {
             // Only send the token to relative URLs i.e. locally.
             xhr.setRequestHeader("X-CSRFToken", getCookie('csrftoken'));
         }
     } 
});

but this didn't work,too!

And I saw a solution that say use ajaxSetup instead of ajaxSend to post data,how can I do this?

like image 824
Asma Gheisari Avatar asked Dec 22 '22 01:12

Asma Gheisari


2 Answers

You should pull the csrfmiddlewaretoken from the dom element:

{'csrfmiddlewaretoken':$( "#csrfmiddlewaretoken" ).val()}

The above is exactly what I do in several places and it works.

Edit just to add some clarity drawing from your material:

<script type="text/javascript">
    $.ajax({
         type:"POST",
         url:"{% url DrHub.views.ajxTest %}",
         data: {
                'start': $('#id_startTime').val(),
                'end': $('#id_endTime').val(),
                'csrfmiddlewaretoken':$( "#csrfmiddlewaretoken" ).val()
         },
         success: function(data){
             alert(data);
         }
    });
</script>
like image 71
James R Avatar answered May 09 '23 23:05

James R


There's also another shortcut to this. I wouldn't know if the security thing here is of so much value and importance. I ran into this problem but there seems to be a lot of hacks around this that end up trying to submit the csrftoken from an existing cookie. I don't know what would happen if this cookie does not exist or was not set.

My approach was to add a @csrf_exempt to the view that processes the ajax post. You import the csrf_exempt from django.views.decorators.csrf

Like this:

from django.views.decorators.csrf import csrf_exempt

And than, from the view method:

@csrf_exempt
def the_method_to_be_called(request):

...

see this link

like image 33
Peter Avatar answered May 09 '23 23:05

Peter