Equivalent to 'cut' on Windows [duplicate]

Question

I have a file which has entries as below.

/a/b/c/d/e/f
/a/b/c/g/k/l/f/j/h
/a/b/c/i/m/n/p

I need a command in Windows which would remove the '/a/b/c' part from the file.

The output file should look like

d/e/f
g/k/l/f/j/h
i/m/n/p

I tried using the for command with / as the delimiter, but I couldn't get the expected result. How can I do this?

Answer 1

@echo off

(for /f "tokens=3,* delims=/" %%a in (input.txt) do echo %%b) > output.txt

And the "trick" is to ask for the third token and the rest of the line.

To use it directly from the command line:

(for /f "tokens=3,* delims=/" %a in (input.txt) do @echo %b) > output.txt

The escaped percent signs are simplified and, as from command line the echo off is not enabled by default, the @ before echo is needed.

Answer 2

PowerShell:

get-content test.txt | foreach-object {
  $_ -replace '/a/b/c/',''
} | out-file test2.txt