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“===” equivalent in Java

Tags:

java

operators

While comparing two values in Java, how do you test if both, the type and the value, are equivalent?

I know in JavaScript === can be used to accomplish this, so I tried that in Java, but it didn’t work.

I know this is a simple question, but I tried looking it up and I couldn’t find out what it was.

like image 895
JavaCakes Avatar asked Jun 20 '19 11:06

JavaCakes


People also ask

Is there a === in Java?

There is no === operator for comparison. When you want to compare two references, you should check - 1. If they are pointing to same object.

Is == and === the same?

The main difference between the == and === operator in javascript is that the == operator does the type conversion of the operands before comparison, whereas the === operator compares the values as well as the data types of the operands.

What is the difference between === and == in Java?

KEY DIFFERENCES:= is used for assigning values to a variable, == is used for comparing two variables, but it ignores the datatype of variable whereas === is used for comparing two variables, but this operator also checks datatype and compares two values.

What is triple equal in Java?

Answer. While these are both comparison equality operators, the triple equals, === , is what's called a strict equality operator while the double equals is an equality operator. The strict equality operator will compare both the value and type of the operands (the values on the left/right sides of the operator).


5 Answers

TL;DR

In Java there is not such a comparison operator: ===, but == or equals

A longer explanation

In weakly typed languages such as JavaScript you can use the strict comparison operator (===) because the language allows comparison between variables which have different types.

For example, in JavaScript, you won't get a compile error if you do this:

var x = 10;
var y = 'foo';
console.log(x == y); // false

And it is useful, when you want to compare variables which may hold values that are "equals" but may be of different types.

For example

var x = 10;
var y = '10';
console.log(x == y)  // true
console.log(x === y) // false

In strongly typed languages such as Java, you don't need to use a strict comparison operator because the language already "handles" the type comparison.

For example:

int x = 10;
String y = "10";
System.out.println("10" == y); // true
System.out.println(x == y);    // compile error : Incompatible operand types int and String

So, basically, in Java, there is no need for checking for strictness using === (a syntax error is reported).

In the first place, the compiler will complain when you compare values of different types using the == operator and conversion cannot be performed.

In the previous example of Java code, if you want to make a comparison between x and y you could use equals:

int x = 10;
String y = "10";
System.out.println(y.equals(x)); // compile warning: Unlikely argument type for equals(): int seems to be unrelated to String

As a side note, notice the equals method cannot be called on primitive types.

Some useful readings are:

  • 15.21. Equality Operators
  • What is the difference between a strongly typed language and a statically typed language?
  • What issues should be considered when overriding equals and hashCode in Java?
like image 63
lealceldeiro Avatar answered Oct 18 '22 02:10

lealceldeiro


I made a function which replicates the functionality of === of Javascript in Java

static boolean compareData(Object v1, Object v2)
{
    if(v1 != null && v2 != null)
        return (v1.getClass() == v2.getClass() && (v1.toString().equals(v2.toString())));
    else
    {
        return (v1 == null ? v2 == null : v1.equals(v2));
    }
}

I was able to pass values of any data type (except array) to this function as well as get true only if the data type and the values match else it returns false. Derived data types like List and HashMap also work.

Call to this function looks like this:

float s1 = 0.f;
float s2 = 0.1f;

System.out.println(compareData(s1, s2)); //Returns false

float s1 = 0.0f;
float s2 = 0.0f;

System.out.println(compareData(s1, s2)); //Returns true

float s1 = 0.1f;
String s2 = "0.1f";

System.out.println(compareData(s1, s2)); //Returns false 

String s1 = "sdf";
String s2 = null;

System.out.println(compareData(s1, s2)); //Returns false 

String s1 = null;
String s2 = null;

System.out.println(compareData(s1, s2)); //Returns true

and so on...

Update: I managed to compare arrays also, following is the code snippet, but, I haven't tested this code intensively but worked for every test case I performed.

if(s1 != null && s2 != null)
    if(s1.getClass().isArray() && s2.getClass().isArray())
        compareDatab = s1.getClass().equals(s2.getClass()) && (Arrays.toString(s1).equals(Arrays.toString(s2)));
    else
        compareDatab = compareData(s1, s2);
else
    compareDatab = compareData(s1, s2);

Usage of the above snippet (Following initializations should be done prior to above code snippet,smh :P):

//s1 and s2 can be anything including Arrays and non-Array...
int[] s1 = {1,2,3};
int[] s2 = {1,2,3};
//compareDatab gives true

int[] s1 = {1,2,4};
int[] s2 = {1,2,3};
//compareDatab gives false

float[] s1 = {1,2,3};
int[] s2 = {1,2,3};
//compareDatab gives false

Where compareData() is the same function as stated prior in this answer.

Hope this proves useful to you. :)

like image 6
FutureJJ Avatar answered Oct 18 '22 04:10

FutureJJ


There is no concept of truthy and falsy in Java, thus there is no strict comparison operator.

like image 4
Murat Karagöz Avatar answered Oct 18 '22 04:10

Murat Karagöz


=== is useful in weak typed languages, such as Javascript, because it verifies that the objects being compared are of the same type and avoids implicit conversions.

=== has absolutely no use in a strongly typed language such as Java because you can't compare variables of different types without writing a specific method for doing this.

like image 4
Istiaque Hossain Avatar answered Oct 18 '22 03:10

Istiaque Hossain


In Java you can compare primitive types like int, double, char, long, float by using '=='. In this case values are compared. For the comparison of objects this is not sufficient because '==' evaluates only to 'true' if the identities of the compared objects are the same - 'identity' is the memory address where the object is stored. This is due to the fact that all classes inherit implicitly all methods provided by the 'Object' class and where the 'equals()'-method contains only a basic implementation. Because of this any class whose objects are involved in comparisons, used in data structures or outside it's own package should contain a solid implementation of equals() and hashCode()-method to provide correct functionality.

Regard following implementation:

public class MyClass {

  private final int val;
  private final String name;

  public MyClass(int val, String name) {
     this.val = val;
     this.name = name;
  }

  public int getVal() { return val; }

  public String getName() { return name; }

  public boolean equals(Object o) {
     if(o == null) return false;
     if(this == o) return true;
     if(!this.getClass().getSimpleName().equals(o.getClass().getSimpleName()) return false;

     MyClass other = (MyClass) o;

     return this.getVal() == other.getVal() && this.getName().equals(other.getName());
  }

  public int hashCode() { ... }

}

Also check out official Java API for further information https://docs.oracle.com/javase/7/docs/api/java/lang/Object.html .

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eulersexception Avatar answered Oct 18 '22 04:10

eulersexception