EOF Error in python Hackerrank

Question

Trying to solve a problem but the compiler of Hackerrank keeps on throwing error EOFError while parsing: dont know where is m i wrong.

#!usr/bin/python

b=[]
b=raw_input().split()
c=[]
d=[]
a=raw_input()
c=a.split()
f=b[1]
l=int(b[1])
if(len(c)==int(b[0])):          
    for i in range(l,len(c)):
        d.append(c[i])
        #print c[i]
    for i in range(int(f)):
        d.append(c[i])
        #print c[i]
for j in range(len(d)):
    print d[j],

i also tried try catch to solve it but then getting no input.

try:
    a=input()
    c=a.split()
except(EOFError):
    a=""

input format is 2 spaced integers at beginning and then the array

the traceback error is:

Traceback (most recent call last):
  File "solution.py", line 4, in <module>
    b=raw_input().split()
EOFError: EOF when reading a line

Answer 1

There are several ways to handle the EOF error.

1.throw an exception:

while True:
  try:
    value = raw_input()
    do_stuff(value) # next line was found 
  except (EOFError):
    break #end of file reached

2.check input content:

while True:
  value = raw_input()
  if (value != ""):
    do_stuff(value) # next line was found 
  else:
    break 

3. use sys.stdin.readlines() to convert them into a list, and then use a for-each loop. More detailed explanation is Why does standard input() cause an EOF error

import sys 

# Read input and assemble Phone Book
n = int(input())
phoneBook = {}
for i in range(n):
    contact = input().split(' ')
    phoneBook[contact[0]] = contact[1]

# Process Queries
lines = sys.stdin.readlines()  # convert lines to list
for i in lines:
    name = i.strip()
    if name in phoneBook:
        print(name + '=' + str( phoneBook[name] ))
    else:
        print('Not found')

Answer 2

I faced the same issue. This is what I noticed. I haven't seen your "main" function but Hackerrank already reads in all the data for us. We do not have to read in anything. For example this is a function def doSomething(a, b):a and b whether its an array or just integer will be read in for us. We just have to focus on our main code without worrying about reading. Also at the end make sure your function return() something, otherwise you will get another error. Hackerrank takes care of printing the final output too. Their code samples and FAQs are a bit misleading. This was my observation according to my test. Your test could be different.

Answer 3

It's because your function is expecting an Input, but it was not provided. Provide a custom input and try to compile it. It should work.