This is how I add query params to a base URL:
let baseURL: URL = ...
let queryParams: [AnyHashable: Any] = ...
var components = URLComponents(url: baseURL, resolvingAgainstBaseURL: false)
components?.queryItems = queryParams.map { URLQueryItem(name: $0, value: "\($1)") }
let finalURL = components?.url
The problem emerges when one of the values contains a +
symbol. For some reason it's not encoded to %2B
in the final URL, instead, it stays +
. If I do encoding myself and pass %2B
, NSURL
encodes %
and the 'plus' becomes %252B
.
The question is how can I have %2B
in the instance of NSURL
?
P.S. I know, I wouldn't even have this problem if I constructed a query string myself and then simply pass a result to the NSURL
's constructor init?(string:)
.
Introducing URLComponents A few years ago, Apple added a type to the Foundation framework that makes working with URLs easier and more elegant, the URLComponents structure in Swift or, if you prefer Objective-C, the NSURLComponents class. Both types are available on iOS 7.0+, tvOS 9.0+, macOS 10.9+, and watchOS 2.0+.
Percent-encoding is a mechanism to encode 8-bit characters that have specific meaning in the context of URLs. It is sometimes called URL encoding. The encoding consists of substitution: A '%' followed by the hexadecimal representation of the ASCII value of the replace character.
A single name-value pair from the query portion of a URL.
addingPercentEncoding(withAllowedCharacters:)Returns a new string made from the receiver by replacing all characters not in the specified set with percent-encoded characters.
Constructing URL is a routine task that every Swift developers do when building an iOS application. It’s very important to make sure the URL we construct are safe and correctly encoded using the percent encoding format. The most simple and crash prone approach to construct an URL is using the URL Struct String initalizer passing the raw string.
URL Encode A String Use the Stringmethod addingPercentEncoding(withAllowedCharacters:)to URL encode a string directly: var decoded = "url components" var encoded = decoded.addingPercentEncoding( withAllowedCharacters: .urlQueryAllowed ) // encoded is "url%20components" URL Property Examples URLs and Strings
URLComponents will automatically URL encode query items that contain disallowed characters: Use the String method addingPercentEncoding (withAllowedCharacters:) to URL encode a string directly: That’s it! By using URL, URLComponents, and URLQueryItem you can create custom urls, parse URL formats, and encode URL query items in Swift.
URLComponentswill automatically URL encode query items that contain disallowed characters: var components = URLComponents() components.queryItems = [ URLQueryItem(name: "page", value: "url components") ] // "?page=url%20components" components.string URL Encode A String
As pointed out in the other answers, the "+" character is valid in
a query string, this is also stated in the
queryItems
documentation:
According to RFC 3986, the plus sign is a valid character within a query, and doesn't need to be percent-encoded. However, according to the W3C recommendations for URI addressing, the plus sign is reserved as shorthand notation for a space within a query string (for example,
?greeting=hello+world
).
[...]
Depending on the implementation receiving this URL, you may need to preemptively percent-encode the plus sign character.
And the W3C recommendations for URI addressing state that
Within the query string, the plus sign is reserved as shorthand notation for a space. Therefore, real plus signs must be encoded. This method was used to make query URIs easier to pass in systems which did not allow spaces.
This can be achieved by "manually" building the percent encoded query string, using a custom character set:
let queryParams = ["foo":"a+b", "bar": "a-b", "baz": "a b"]
var components = URLComponents()
var cs = CharacterSet.urlQueryAllowed
cs.remove("+")
components.scheme = "http"
components.host = "www.example.com"
components.path = "/somepath"
components.percentEncodedQuery = queryParams.map {
$0.addingPercentEncoding(withAllowedCharacters: cs)!
+ "=" + $1.addingPercentEncoding(withAllowedCharacters: cs)!
}.joined(separator: "&")
let finalURL = components.url
// http://www.example.com/somepath?bar=a-b&baz=a%20b&foo=a%2Bb
Another option is to "post-encode" the plus character in the generated percent-encoded query string:
let queryParams = ["foo":"a+b", "bar": "a-b", "baz": "a b"]
var components = URLComponents()
components.scheme = "http"
components.host = "www.example.com"
components.path = "/somepath"
components.queryItems = queryParams.map { URLQueryItem(name: $0, value: $1) }
components.percentEncodedQuery = components.percentEncodedQuery?
.replacingOccurrences(of: "+", with: "%2B")
let finalURL = components.url
print(finalURL!)
// http://www.example.com/somepath?bar=a-b&baz=a%20b&foo=a%2Bb
URLComponents is behaving correctly: the +
is not being percent-encoded because it is legal as it stands. You can force the +
to be percent-encoded by using .alphanumerics
, as explained already by Forest Kunecke (I got the same result independently but he was well ahead of me in submitting his answer!).
Just a couple of refinements. The OP's value: "\($1)"
is unnecessary if this is a string; you can just say value:$1
. And, it would be better to form the URL from all its components.
This, therefore, is essentially the same solution as Forest Kunecke, but I think it is more canonical and it is certainly more compact ultimately:
let queryParams = ["hey":"ho+ha"]
var components = URLComponents()
components.scheme = "http"
components.host = "www.example.com"
components.path = "/somepath"
components.queryItems = queryParams.map {
URLQueryItem(name: $0,
value: $1.addingPercentEncoding(withAllowedCharacters: .alphanumerics)!)
}
let finalURL = components.url
EDIT Rather better, perhaps, after suggested correction from Martin R: we form the entire query and percent-encode the pieces ourselves, and tell the URLComponents that we have done so:
let queryParams = ["hey":"ho+ha", "yo":"de,ho"]
var components = URLComponents()
components.scheme = "http"
components.host = "www.example.com"
components.path = "/somepath"
var cs = CharacterSet.urlQueryAllowed
cs.remove("+")
components.percentEncodedQuery = queryParams.map {
$0.addingPercentEncoding(withAllowedCharacters: cs)! +
"=" +
$1.addingPercentEncoding(withAllowedCharacters: cs)!
}.joined(separator:"&")
// ---- Okay, let's see what we've got ----
components.queryItems
// [{name "hey", {some "ho+ha"}}, {name "yo", {some "de,ho"}}]
components.url
// http://www.example.com/somepath?hey=ho%2Bha&yo=de,ho
You can simply encode components.percentEncodedQuery
after query items was inserted.
let characterSet = CharacterSet(charactersIn: "/+").inverted
components.percentEncodedQuery = components.percentEncodedQuery?.addingPercentEncoding(withAllowedCharacters: characterSet)
Can you try using addingPercentEncoding(withAllowedCharacters: .alphanumerics)
?
I just put together a quick playground demonstrating how this works:
//: Playground - noun: a place where people can play
let baseURL: URL = URL(string: "http://example.com")!
let queryParams: [AnyHashable: Any] = ["test": 20, "test2": "+thirty"]
var components = URLComponents(url: baseURL, resolvingAgainstBaseURL: false)
var escapedComponents = [String: String]()
for item in queryParams {
let key = item.key as! String
let paramString = "\(item.value)"
// percent-encode any non-alphanumeric character. This is NOT something you typically need to do. User discretion advised.
let escaped = paramString.addingPercentEncoding(withAllowedCharacters: .alphanumerics)
print("escaped: \(escaped)")
// add the newly escaped components to our dictionary
escapedComponents[key] = escaped
}
components?.queryItems = escapedComponents.map { URLQueryItem(name: ($0), value: "\($1)") }
let finalURL = components?.url
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With