I've found a strange looking piece of code in a project I have to maintain. There's an empty array member of a class which doesn't lead to an compiler error. I've tested some variations of such a code with MSVC 10.0:
template<class T> struct A {
int i[];
}; // warning C4200: nonstandard extension used : zero-sized array in struct/union
template<class T> struct B { static int i[]; };
template<class T> int B<T>::i[];
struct C {
int i[];
}; //warning C4200: nonstandard extension used : zero-sized array in struct/union
template<class T> struct D { static int i[]; };
template<class T> int D<T>::i[4];
template<> int D<int>::i[] = { 1 };
int main()
{
A<void> a;
B<void> b;
C c;
D<void> d0;
D<int> d1;
a.i[0] = 0; // warning C4739: reference to variable 'a' exceeds its storage space
b.i[0] = 0; // warning C4789: destination of memory copy is too small
c.i[0] = 0; // warning C4739: reference to variable 'c' exceeds its storage space
int i[]; // error C2133: 'i' : unknown size
d0.i[0] = 0; // ok
d0.i[1] = 0; // ok
return 0;
}
The error message at int i[]
is absolutely sensible to me. The code which is shown with class D
is well-formed standard C++. But what's about the classes A
, B
and C
? What kind of types are the member variables int i[]
in this classes?
EDIT:
your doubt is explained by the definition of the extension to the language, which allows for zero-sized arrays at the end of structs/unions. I have not tried it, but if you declare another member after the zero-sized array, it should fail.
so, if you allocate a variable on the stack, you have to know its size; the exception to the rule is when allocating an array at the end of a struct/union, where some C-typical trickery is possible.
In c++ this raises a warning because the default copy constructor and assignment operator will probably not work.
PREVIOUS ANSWER:
The compiler warns you about the fact that you are trying to define an array with zero size. This is not allowed in standard C/C++.
Let's see the differences class by class.
In class D:
template<class T> struct D { static int i[]; };
it works because you are just declaring the type of a static member variable. For this to link, you need also defining the actual array, in a definition statement like you do:
template<> int D<int>::i[] = { 1 };
here you also specify the size of the array through the initializer.
With class B, you are doing something similar, but the definition is:
template<class T> int B<T>::i[];
i.e., you don't specify the size and get the warning.
With class A, more of the same, you are defining a member variable of type array without the size.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With