employee.hashCode() Vs employee.getClass().hashcode() in Java

Question

I have below program.

Employee employee1 = new Employee("Raghav1", 101);

Employee employee2 = new Employee("Raghav", 100);

// #1
System.out.println(employee1.hashCode() == employee2.hashCode()); 

// #2
System.out.println(employee1.getClass().hashCode() == employee2.getClass().hashCode());

The statement 1 returns false as both employee objects are different but why the statement 2 returns true.

Can anyone explain the difference between the above statements?

Answer 1

The first statement compares the hash code of two employee instances. This is probably a bad implementation of the hashCode() method, since it seems as though both instances should be equal, and hence should have equal hash codes.

The second statement gets the class of each instance and compares the hash codes of the classes. Since both employee1 and employee2 are instances of Employee, they both have the same class, and you're just comparing two calls to the same hashCode() method, which are bound to return the same value.