EmguCV TypeInitializationException

Question

i really a newbie with EgmuCV

i try to capture images from webcam with the following code:

//Program.cs (Winform)
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

using Emgu.CV;
using Emgu.CV.UI;
using Emgu.Util;
using Emgu.CV.Structure;

namespace EgmuCVTest
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            Capture cp = new Capture();
            ImageViewer imv = new ImageViewer();

            Application.Idle += new EventHandler(delegate(object s, EventArgs ea)
            {
                imv.Image = cp.QueryFrame();
            });

            imv.ShowDialog();

        }
    }
}

i get the follow error:

i check and have all necesary dll in the .exe folder

Answer 1

After experiencing this same problem for a while, I found the instructions for solving this (TypeInitializer Exception) are incomplete.

1. For a basic app, you need cvextern.dll, Emgu.CV.dll, Emgu.CV.UI.dll, Emgu.Util.dll in the .EXE's directory.

2. You need a x86(x64) dir in the .exe directory and inside "x86" dir you need opencv_calib3dXXX.dll, opencv_contribXXX.dll, opencv_coreXXX.dll, opencv_features2dXXX.dll, opencv_highguiXXX.dll, opencv_imgprocXXX.dll, opencv_legacyXXX.dll, opencv_mlXXX.dll, opencv_objectdetectXXX.dll, opencv_videoXXX.dll and cudart32_42_9.dll, npp32_42_9.dll, opencv_flann240.dll

The app will work as soon as you include all of the required DLLs.

Answer 2

I'm using Emgu 3.0 64 bit and the only thing i need to do to fix this problem is change the build type in my project into x64.

Right click on your project's name -> Properties -> Build -> Platform Target -> x64

refer to http://www.codeproject.com/Articles/257502/Creating-Your-First-EMGU-Image-Processing-Project

hope it helps someone.