Ellipsis in array initialization in C kernel module

Question

I was examining some code on github https://github.com/umlaeute/v4l2loopback/blob/master/v4l2loopback.c and came across this line, which baffles me. Is this some incredibly cool kernel macro or gcc feature that I don't know about? What does the = -1 do?

static int video_nr[MAX_DEVICES] = { [0 ... (MAX_DEVICES-1)] = -1 };
module_param_array(video_nr, int, NULL, 0444);
MODULE_PARM_DESC(video_nr, "video device numbers (-1=auto, 0=/dev/video0, etc.)");

The line in question is the first, the next two given for context (this is creating a cmdline-specifiable parameter using a kernel macro http://lxr.free-electrons.com/source/include/linux/moduleparam.h#L103 )

Anyway, what is going on with the array initialization? How does that syntax work?

Answer 1

You've found an example of designated initializers. C99 & C11 don't go quite as far as your example, but they have some pretty flexible support for this kind of behaviour. Your specific example (using the ...) is a GCC extension. From the link:

To initialize a range of elements to the same value, write [first ... last] = value. This is a GNU extension. For example,

int widths[] = { [0 ... 9] = 1, [10 ... 99] = 2, [100] = 3 };

So that means your example is creating an array of size MAX_DEVICES and initializing every element in that array to -1.

For reference, the only standard-supported behaviour is to assign specific indices, rather than ranges:

[constant-expression] = initializer-value

There is a more complicated example in my copy of the spec:

int a[MAX] = {
            1, 3, 5, 7, 9, [MAX-5] = 8, 6, 4, 2, 0
};

Which initializes the first five and last five elements of the array to explicit values. The middle values (if any) would be 0.