I've two lists A and B. I'd like to find out indexes of elements in A that match elements of listB. Something like this:
ArrayList listA = new ArrayList();
listA.add(1);listA.add(2);listA.add(3);listA.add(4);
ArrayList listB = new ArrayList();
listB.add(2);listB.add(4);
ArrayList listC = new ArrayList();
for(int i=0; i<listB.size();i++) {
int element = listB.get(i);
for(int j=0; j<listA.size(); j++) {
if(listA.get(j) == element) listC.add(j);
}
}
I guess that's one ugly way to doing it. What is the best way to finding all the indexes of A that match all elements in B? I believe there exists a method called containsAll in collections api - don't think it returns matching indexes.
You can use the index() method to find the index of the first element that matches with a given search object. The index() method returns the first occurrence of an element in the list. In the above example, it returns 1, as the first occurrence of “Bob” is at index 1.
The elements of a list can be accessed by an index. To do that, you name the list, and then inside of a pair of square brackets you use an index number, like what I'm showing right here. 00:17 That allows access to individual elements within the list.
One of the most basic ways to get the index positions of all occurrences of an element in a Python list is by using a for loop and the Python enumerate function. The enumerate function is used to iterate over an object and returns both the index and element.
If you had to use an ArrayList
, you could create a HashSet
from the ArrayList
. This would make the call to contains
O(1). It would take O(n) to create the HastSet
. If you could start with a HashSet
, that would be best.
public static void main(String[] args)
{
List listA = new ArrayList();
listA.add(1);
listA.add(2);
listA.add(3);
listA.add(4);
List listB = new ArrayList();
listB.add(2);
listB.add(4);
Set hashset = new HashSet(listA);
for(int i = 0; i < listB.size(); i++)
{
if(hashset.contains(listB.get(i)))
{
listC.add(i);
System.out.println(i);
}
}
}
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