The title is pretty much clear I think.
I was wondering if there's a certain efficiency overhead when using IEqualityComparer
in a Dictionary<K,V>
how does it all work when providing one?
Thanks
-1 Dictionary does NOT use GetHashCode() to determine if two keys are equal. That is, a dictionary can contain separate entries whose keys have the same hash code. The dictionary may be less efficient, but it will still work.
IEqualityComparer is a very important interface for comparer tasks in the LinQ world. The next extended methods have an overload with this parameter type: Contains, Distinct, Except, Intersect, GrouBy, GroupJoin, Join, SecuenceEqual, ToDictionary, ToLookUp and Union.
Is it Faster?
Coming from a gamedev perspective, if your key is a value type (struct, primitive, enum, etc.) providing your own EqualityComparer<T>
is significantly faster - due to the fact the EqualityComparer<T>.Default
boxes the value.
As a real-world example, the Managed DirectX billboard sample used to run at ~30% of the speed of the C++ version; where all the other samples were running at ~90%. The reason for this was that the billboards were being sorted using the default comparer (and thus being boxed), as it turns out 4MB of data was being copied around every frame thanks to this.
How does it work?
Dictionary<K,V>
will provide EqualityComparer<T>.Default
to itself via the default constructor. What the default equality comparer does is (basically, notice how much boxing occurs):
public void GetHashCode(T value)
{
return ((object)value).GetHashCode();
}
public void Equals(T first, T second)
{
return ((object)first).Equals((object)second);
}
Why would I ever use it?
It's quite common to see this kind of code (when trying to have case-insensitive keys):
var dict = new Dictionary<string, int>();
dict.Add(myParam.ToUpperInvariant(), fooParam);
// ...
var val = dict[myParam.ToUpperInvariant()];
This is really wasteful, it is better to just use a StringComparer on the constructor:
var dict = new Dictionary<string, int>(StringComparer.OrdinalIgnoreCase);
Is it faster (redux)?
In this specific scenario it is a lot faster, because ordinal string comparisons are the fastest type of string comparison you can do. A quick benchmark:
static void Main(string[] args)
{
var d1 = new Dictionary<string, int>();
var d2 = new Dictionary<string, int>(StringComparer.OrdinalIgnoreCase);
d1.Add("FOO", 1);
d2.Add("FOO", 1);
Stopwatch s = new Stopwatch();
s.Start();
RunTest1(d1, "foo");
s.Stop();
Console.WriteLine("ToUpperInvariant: {0}", s.Elapsed);
s.Reset();
s.Start();
RunTest2(d2, "foo");
s.Stop();
Console.WriteLine("OrdinalIgnoreCase: {0}", s.Elapsed);
Console.ReadLine();
}
static void RunTest1(Dictionary<string, int> values, string val)
{
for (var i = 0; i < 10000000; i++)
{
values[val.ToUpperInvariant()] = values[val.ToUpperInvariant()];
}
}
static void RunTest2(Dictionary<string, int> values, string val)
{
for (var i = 0; i < 10000000; i++)
{
values[val] = values[val];
}
}
// ToUpperInvariant: 00:00:04.5084119
// OrdinalIgnoreCase: 00:00:02.1211549
// 2x faster.
Reservations
It is possible to eliminate the boxing overhead by implementing an interface on a struct (such as IEquatable<T>
). However, there are many surprising rules for when boxing occurs under these circumstances so I would recommend using the paired interface (e.g. IEqualityComparer<T>
in this case) if at all possible.
Jonathan has a great answer that points out how, using the right equality comparer improves the performance and Jon clarifies in his great answer that Dictionary<K, V>
always uses an IEqualityComparer<T>
which is EqualityComparer<T>.Default
unless you specify another.
The thing I'd like to touch upon is the role of IEquatable<T>
interface when you use the default equality comparer.
When you call the EqualityComparer<T>.Default
, it uses a cached comparer if there is one. If it's the first time you're using the default equality comparer for that type, it calls a method called CreateComparer
and caches the result for later use. Here is the trimmed and simplified implementation of CreateComparer
in .NET 4.5:
var t = (RuntimeType)typeof(T);
// If T is byte,
// return a ByteEqualityComparer.
// If T implements IEquatable<T>,
if (typeof(IEquatable<T>).IsAssignableFrom(t))
return (EqualityComparer<T>)
RuntimeTypeHandle.CreateInstanceForAnotherGenericParameter(
(RuntimeType)typeof(GenericEqualityComparer<int>), t);
// If T is a Nullable<U> where U implements IEquatable<U>,
// return a NullableEqualityComparer<U>
// If T is an int-based Enum,
// return an EnumEqualityComparer<T>
// Otherwise return an ObjectEqualityComparer<T>
But what does it mean for types that implement IEquatable<T>
?
Here, the definition of GenericEqualityComparer<T>
:
internal class GenericEqualityComparer<T> : EqualityComparer<T>
where T: IEquatable<T>
// ...
The magic happens in the generic type constraint (where T : IEquatable<T>
part) because using it does not involve boxing if T
is a value type, no casting like (IEquatable<T>)T
is happening here, which is the primary benefit of generics.
So, let's say we want a dictionary that maps integers to strings.
What happens if we initialize one using the default constructor?
var dict = new Dictionary<int, string>();
EqualityComparer<T>.Default
unless we specify another.EqualityComparer<int>.Default
will check if int implements IEquatable<int>
.int
(Int32
) implements IEquatable<Int32>
.First call to EqualityComparer<T>.Default
will create and cache a generic comparer which may take a little but when initialized, it's a strongly typed GenericEqualityComparer<T>
and using it will cause no boxing or unnecessary overhead whatsoever.
And all the subsequent calls to EqualityComparer<T>.Default
will return the cached comparer, which means the overhead of initialization is one-time only for each type.
So what does it all mean?
T
does not implement IEquatable<T>
or its implementation of IEquatable<T>
does not do what you want it to do.obj1.Equals(obj2)
doesn`t give you the desired result.)Using of StringComparer
in Jonathan's answer is a great example why you would specify a custom equality comparer.
T
implements IEquatable<T>
and the implementation of IEquatable<T>
does what you want it to do.obj1.Equals(obj2)
gives you the desired result).In the latter case, use EqualityComparer<T>.Default
instead.
Dictionary<,>
always uses an IEqualityComparer<TKey>
- if you don't pass one, it uses EqualityComparer<T>.Default
. So the efficiency will depend on how efficient your implementation is compared with EqualityComparer<T>.Default
(which just delegates to Equals
and GetHashCode
).
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