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Edittext inputtype constant value doesnot match

In android xml file im using editext as

<EditText
  android:id="@+id/email"
  android:layout_width="fill_parent"
  android:layout_height="33dp"
  android:inputType="textEmailAddress"
  android:hint="Enter your mail id" />

In java file while validating that editext.

if(editextobj.getInputType()==InputType.TYPE_TEXT_VARIATION_EMAIL_ADDRESS){

}

or

if(getInputType()==(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_EMAIL_ADDRESS)){

}

this condition is not working since editextobj.getInputType() returns 33 whereas developer document gives TYPE_TEXT_VARIATION_EMAIL_ADDRESS constant value as 32

How to validate inputype programatically?

like image 918
Mukesh Avatar asked Dec 26 '13 07:12

Mukesh


2 Answers

The following is happening:
InputType.TYPE_TEXT_VARIATION_EMAIL_ADDRESS value is: 32.
InputType.TYPE_CLASS_TEXT value is: 1.

the (|) is a bitwise OR operation. It's doing modification at the binary level:

Decimal: 32|1 results in 33
Binary: 100000|1 results in 100001 which is 33 in decimal.

editextobj.getInputType() value is 33

like image 71
Red M Avatar answered Sep 26 '22 05:09

Red M


There is nothing wrong with your code. 32 stays for TYPE_TEXT_VARIATION_EMAIL_ADDRESS. Also it's a flag, so you should test it like this. See InputType example(at the top under class overview) for more details.

if(editextobj.getInputType() & InputType.TYPE_TEXT_VARIATION_EMAIL_ADDRESS == 1){

}
like image 45
Ilya Gazman Avatar answered Sep 25 '22 05:09

Ilya Gazman