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I was wondering if there was a syntactically simple way of checking if each element in a numpy array lies between two numbers.
In other words, just as numpy.array([1,2,3,4,5]) < 5 will return array([True, True, True, True, False]), I was wondering if it was possible to do something akin to this:
1 < numpy.array([1,2,3,4,5]) < 5 ... to obtain ...
array([False, True, True, True, False]) I understand that I can obtain this through logical chaining of boolean tests, but I'm working through some rather complex code and I was looking for a syntactically clean solution.
Any tips?
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To check if two NumPy arrays A and B are equal: Use a comparison operator (==) to form a comparison array. Check if all the elements in the comparison array are True.
Using Numpy array, we can easily find whether specific values are present or not. For this purpose, we use the “in” operator. “in” operator is used to check whether certain element and values are present in a given sequence and hence return Boolean values 'True” and “False“.
To compare two arrays and return the element-wise minimum, use the numpy. fmin() method in Python Numpy. Return value is either True or False. Compare two arrays and returns a new array containing the element-wise maxima.
The numpy. array_equiv() function can also be used to check whether two arrays are equal or not in Python. The numpy. array_equiv() function returns True if both arrays have the same shape and all the elements are equal, and returns False otherwise.
One solution would be:
import numpy as np a = np.array([1, 2, 3, 4, 5]) (a > 1) & (a < 5) # array([False, True, True, True, False]) Another would be to use numpy.any, Here is an example
import numpy as np a = np.array([1,2,3,4,5]) np.any((a < 1)|(a > 5 )) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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