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each wait until finish $.ajax , and then continue

Tags:

jquery

ajax

each

    function genTask(elem){
    elem.each(function(){
        $this=$(this).parent('.cntTasks');
        var pattern=/taskId-(.*)$/
        var idTask=$this.attr('id').match(pattern);
        var data='id_task='+idTask[1];
        if(typeof jsVar2 !='undefined') data+=jsVar2;
        $.ajax({
             type: "POST",
             url: domain+"/view_tasks/gen_tasks/",
             dataType: 'html',
             data: data,
             success: function(dt){
                $this.find('.contChildTasks').html(dt);
                childs=$this.children('.taskDesc').find('.has_child');
                if(childs.length!=0)
                    genTask(childs);
                }
             }
        });
        $this.find('.taskDesc').show();

    });
}

if(typeof jsVar2 !='undefined') genTask($('.cntTasks .has_child'));


});    

how is possible to make $.each to wait until action $.ajax will be finished , and then continue loop , i cannot get $this var , because it has the last value , sorry for my English , THANK YOU !!!!

like image 235
mIRU Avatar asked Dec 28 '11 14:12

mIRU


1 Answers

Option 1: Switch to next element in your array in the success handler.

Option 2: Make ajax requests synchronously:

  • global:

     $.ajaxSetup({ async: false });
    
  • or directly in the request:

     $.ajax({
         async: false,
         type: "POST",
         url: domain+"/view_tasks/gen_tasks/",
         dataType: 'html',
         data: data,
         success: function(dt){
            $this.find('.contChildTasks').html(dt);
            childs = $this.children('.taskDesc').find('.has_child');
            if(childs.length != 0) {
                genTask(childs);
            }
         }
    });
    
like image 164
Samich Avatar answered Oct 20 '22 01:10

Samich