Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Dynamically Create Droppable Element

I'm implementing drag and drop using the jQuery UI Draggable and Droppable widgets. (Sortable didn't provide quite enough flexibility for me.)

As I drag, I'm dynamically creating a drop placeholder element to show precisely where a drop would be placed.

But how can I make this drop placeholder droppable itself? If I create it and then immediately call the droppable() method on it, this has no effect. And so if they user drops directly over a drop placeholder, how could I detect this?

You can see what I have so far at http://jsbin.com/uciviy/14.

like image 279
Jonathan Wood Avatar asked May 27 '26 07:05

Jonathan Wood


1 Answers

It is possible to create a div dynamically and make it droppable.

You can either create the div through JQuery and then make it droppable, or create a droppable div when the drag event begins on a draggable element and that element can be dropped on the new div created. This is possible like so:

$( "<div>Dynamic Droppable Div</div>" ).droppable( dropOptions ).appendTo( "#anotherDiv" );

Fiddle here.

like image 103
mccannf Avatar answered Jun 03 '26 01:06

mccannf