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Dynamic variable name in python

Tags:

python

django

I'd like to call a query with a field name filter that I wont know before run time... Not sure how to construct the variable name ...Or maybe I am tired.

field_name = funct()
locations = Locations.objects.filter(field_name__lte=arg1)

where if funct() returns name would equal to

locations = Locations.objects.filter(name__lte=arg1)

Not sure how to do that ...

like image 407
philgo20 Avatar asked Dec 22 '22 04:12

philgo20


1 Answers

You can create a dictionary, set the parameters and pass this to the function by unpacking the dictionary as keyword arguments:

field_name = funct()
params = {field_name + '__lte': arg1,       # field_name should still contain string
          'some_other_field_name': arg2}

locations = Locations.objects.filter(**params)

# is the same as (assuming field_name = 'some_name'):
# Locations.objects.filter(some_name__lte=arg1, some_other_field_name=arg2)
like image 92
Felix Kling Avatar answered Jan 02 '23 17:01

Felix Kling