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Dynamic mixin in Scala - is it possible?

Tags:

mixins

scala

What I'd like to achieve is having a proper implementation for

def dynamix[A, B](a: A): A with B 

I may know what B is, but don't know what A is (but if B has a self type then I could add some constraints on A). The scala compiler is happy with the above signature, but I could not yet figure out how the implementation would look like - if it is possible at all.

Some options that came to my mind:

  • Using reflection/dynamic proxy.
    • Simplest case: A is an interface on Java level + I can instantiate B and it has no self type. I guess it would not be too hard (unless I run into some nasty, unexpected problems):
      create a new B (b), and also a proxy implementing both A and B and using an invocation handler delegating to either a or b.
    • If B can not be instantiated I could still create a subclass of it, and do as it was described above. If it also has a self type I would probably need some delegation here and there, but it may still work.
    • But what if A is a concrete type and I can't find a proper interface for it?
    • Would I run into more problems (e.g. something related to linearization, or special constructs helping Java interoperability)?
  • Using a kind of wrapping instead of a mixin and return B[A], a is accessible from b.
    Unfortunately in this case the caller would need to know how the nesting is done, which could be quite inconvenient if the mixing in/wrapping is done several times (D[C[B[A]]]) as it would need to find the right level of nesting to access the needed functionality, so I don't consider it a solution.
  • Implementing a compiler plugin. I have zero experience with it but my gut feeling is that it would not be trivial. I think Kevin Wright's autoproxy plugin has a bit similar goal, but it would not be enough for my problem (yet?).

Do you have any other ideas that might work? Which way would you recommend? What kind of "challenges" to expect?
Or should I forget it, because it is not possible with the current Scala constraints?

Intention behind my problem: Say I have a business workflow, but it's not too strict. Some steps have fixed order, but others do not, but at the end all of them has to be done (or some of them required for further processing).
A bit more concrete example: I have an A, I can add B and C to it. I don't care which is done first, but at the end I'll need an A with B with C.

Comment: I don't know too much about Groovy but SO popped up this question and I guess it's more or less the same as what I'd like, at least conceptional.

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Sandor Murakozi Avatar asked Jul 15 '10 09:07

Sandor Murakozi


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1 Answers

I believe this is impossible to do strictly at runtime, because traits are mixed in at compile-time into new Java classes. If you mix a trait with an existing class anonymously you can see, looking at the classfiles and using javap, that an anonymous, name-mangled class is created by scalac:

class Foo {   def bar = 5 }  trait Spam {   def eggs = 10 }  object Main {   def main(args: Array[String]) = {     println((new Foo with Spam).eggs)   } } 

scalac Mixin.scala; ls *.class returns

Foo.class Main$.class Spam$class.class Main$$anon$1.class Main.class Spam.class

While javap Main\$\$anon\$1 returns

Compiled from "mixin.scala"  public final class Main$$anon$1 extends Foo implements Spam{     public int eggs();     public Main$$anon$1(); } 

As you can see, scalac creates a new anonymous class that is loaded at runtime; presumably the method eggs in this anonymous class creates an instance of Spam$class and calls eggs on it, but I'm not completely sure.

However, we can do a pretty hacky trick here:

import scala.tools.nsc._; import scala.reflect.Manifest  object DynamicClassLoader {   private var id = 0   def uniqueId = synchronized {  id += 1; "Klass" + id.toString } }  class DynamicClassLoader extends      java.lang.ClassLoader(getClass.getClassLoader) {   def buildClass[T, V](implicit t: Manifest[T], v: Manifest[V]) = {      // Create a unique ID     val id = DynamicClassLoader.uniqueId      // what's the Scala code we need to generate this class?     val classDef = "class %s extends %s with %s".       format(id, t.toString, v.toString)      println(classDef)      // fire up a new Scala interpreter/compiler     val settings = new Settings(null)     val interpreter = new Interpreter(settings)      // define this class     interpreter.compileAndSaveRun("<anon>", classDef)      // get the bytecode for this new class     val bytes = interpreter.classLoader.getBytesForClass(id)      // define the bytecode using this classloader; cast it to what we expect     defineClass(id, bytes, 0, bytes.length).asInstanceOf[Class[T with V]]   }  }   val loader = new DynamicClassLoader  val instance = loader.buildClass[Foo, Spam].newInstance instance.bar // Int = 5 instance.eggs // Int = 10 

Since you need to use the Scala compiler, AFAIK, this is probably close to the cleanest solution you could do to get this. It's quite slow, but memoization would probably help greatly.

This approach is pretty ridiculous, hacky, and goes against the grain of the language. I imagine all sorts of weirdo bugs could creep in; people who have used Java longer than me warn of the insanity that comes with messing around with classloaders.

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stephenjudkins Avatar answered Oct 04 '22 12:10

stephenjudkins