Menu
A 2D array is stored in the computer's memory one row following another. The address of the first byte of memory is considered as the memory location of the entire 2D array.
The code snippet that shows this is as follows. int row = 2, col = 3; int *arr = (int *)malloc(row * col * sizeof(int)); int i, j; for (i = 0; i < row; i++) for (j = 0; j < col; j++) *(arr + i*col + j) = i + j; Then the values of the 2-D array are displayed.
dynamically allocated arrays To dynamically allocate space, use calls to malloc passing in the total number of bytes to allocate (always use the sizeof to get the size of a specific type). A single call to malloc allocates a contiguous chunk of heap space of the passed size.
I have declared an array char **arr; How to initialize the memory for the 2D char array.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With