I have added some const character in my file as under. The error i get is duplicate symbol _xyz(say). What is the problem with it and how could i get out of this.
const char* xyz = "xyz"; class Abc { public: Abc() { } };
Solution. Duplicate symbols occur when you have both added an implementation file (. cpp) to your project and #included it. This way, the implementation file (. cpp) gets compiled twice: once as a module in your project (as it is added to your project) and subsequently as a piece of #included code.
duplicate symbol _OBJC_IVAR_$_BLoginViewController._hud in: 17 duplicate symbols for architecture x86_64. "Means that you have loaded same functions twice. As the issue disappear after removing -ObjC from Other Linker Flags, this means that this option result that functions loads twice:"
If this is in a header file, you're defining xyz
every time you #include
it.
You can change the declaration as @R Samuel Klatchko shows. The usual way (if the data isn't const
) is like this:
In Abc.h:
extern char *xyz;
In Abc.cpp:
char *xyz = "xyz";
Edited to add
Note that header guards will not solve this problem:
#ifndef XYZ_H #define XYZ_H ... #endif
Header guards prevent "redefinition" errors, where the same symbol appears twice in the same compilation unit. That's a compiler error.
But even with header guards the definition of xyz
will still appear in every source file that includes it, causing a "duplicate symbol" error, which is a linker error.
It would have been more helpful if the original poster had mentioned that, of course.
The problem is every source file that includes your header file gets it's own copy of xyz
with external linkage.
The easiest way to fix that is to give xyz
internal linkage. You can do that by making the pointer itself const in addition to having the underlying char's const:
const char* const xyz = "xyz";
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