Has anyone had experience with programming the selection of the SIM card, when the phone uses a dual SIM adapter?
Thanks, STeN
Added later: I have found the MultiSim application on the Android Market, which has in its description written that "...Analog dual-sim-adapter users can switch their sim cards...", so is there some API in the Android SDK, which allows the SIM card switch/selection?
Tap on the More options button from the upper-right corner. Its icon looks like three vertical dots. From the dropdown menu, tap on Quick panel layout. If you want the Dual SIM settings shown in the Quick Settings menu, tap on the “Show multi SIM info” option to enable the switch next to it.
If you have a Pixel 3a or later Pixel phone, you can use two SIMs: one physical SIM card and one eSIM. You can choose which SIM to use for which action, like messaging or calling. This option is called Dual SIM Dual Standby (DSDS). DSDS and eSIM work with some mobile carriers.
The best Android phones all come with a dual-SIM card slot, but because of the carrier-driven ecosystem in the U.S., phone manufacturers like Samsung disable this feature in the region. But with the rise of eSIM, you can now get dual-SIM connectivity in North America on just about any phone.
Having two SIM cards lets you keep calls and messages for two numbers separate. So you can give out your numbers to the appropriate people. Depending on the phone you can set it to prompt which number to call out on every time, or have defaults. For instance all outgoing calls on SIM 1 and all text messages on SIM 2.
The current Android platform does not have support for multiple SIMs. A device with such support has been customized for this, so you will need to get information from that device's manufacturer for any facilities they have to interact with it.
Since nobody mentioned it yet, Android finally has added official multisim support on Android 5.1.
But unless your app is only targeting that API (which is currently less than 0.5% of the market) you are on your own with the more obscure solutions mentioned in the other answers.
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