I have been trying to upload a simple file to dropbox using the files_upload() function in python3
Even trying out the code in the tutorial provided on Dropbox's site I get an error and I don't understand why. What am I missing here?
Here is my code:
import dropbox
dbx = dropbox.Dropbox("my_access_token")
data = "asd"
dbx.files_upload(data, '/file.txt')
And here is the error message I get when I try to run it:
Traceback (most recent call last):
File "dbox.py", line 7, in <module>
dbx.files_upload(data, '/file.txt')
File "/usr/local/lib/python3.4/dist-packages/dropbox/base.py", line 1225, in files_upload
f,
File "/usr/local/lib/python3.4/dist-packages/dropbox/dropbox.py", line 249, in request
timeout=timeout)
File "/usr/local/lib/python3.4/dist-packages/dropbox/dropbox.py", line 341, in request_json_string_with_retry
timeout=timeout)
File "/usr/local/lib/python3.4/dist-packages/dropbox/dropbox.py", line 385, in request_json_string
type(request_binary))
TypeError: expected request_binary as binary type, got <class 'str'>
I've tried it different ways:
1.
with open("/home/pi/Desktop/dbox/asd.txt", "rb") as f:
dbx.files_upload(f, '/asd.txt', mute = True)
2.
dbx.files_upload("hello", "")
3.
dbx.files_upload("hello", "/")
but I get the same error every time.
From this documentation, it appears that the first argument to files_upload()
needs to be a bytes object. Which means you got close with:
with open("/home/pi/Desktop/dbox/asd.txt", "rb") as f:
dbx.files_upload(f, '/asd.txt', mute = True)
Try this instead (f.read()
returns a bytes
object):
with open("/home/pi/Desktop/dbox/asd.txt", "rb") as f:
dbx.files_upload(f.read(), '/asd.txt', mute = True)
You could also try passing data.encode(whatever_encoding)
instead of just data
. I am not sure why this is not mentioned in the tutorial that you linked.
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