I have a data frame containing a factor
. When I create a subset of this dataframe using subset
or another indexing function, a new data frame is created. However, the factor
variable retains all of its original levels, even when/if they do not exist in the new dataframe.
This causes problems when doing faceted plotting or using functions that rely on factor levels.
What is the most succinct way to remove levels from a factor in the new dataframe?
Here's an example:
df <- data.frame(letters=letters[1:5], numbers=seq(1:5)) levels(df$letters) ## [1] "a" "b" "c" "d" "e" subdf <- subset(df, numbers <= 3) ## letters numbers ## 1 a 1 ## 2 b 2 ## 3 c 3 # all levels are still there! levels(subdf$letters) ## [1] "a" "b" "c" "d" "e"
Removing Levels from a Factor in R Programming – droplevels() Function. droplevels() function in R programming used to remove unused levels from a Factor. droplevels(x, exclude = if(anyNA(levels(x))) NULL else NA, …)
How do I Rename Factor Levels in R? The simplest way to rename multiple factor levels is to use the levels() function. For example, to recode the factor levels “A”, “B”, and “C” you can use the following code: levels(your_df$Category1) <- c("Factor 1", "Factor 2", "Factor 3") .
Factors are the data objects which are used to categorize the data and store it as levels. They can store both strings and integers. They are useful in the columns which have a limited number of unique values.
Since R version 2.12, there's a droplevels()
function.
levels(droplevels(subdf$letters))
All you should have to do is to apply factor() to your variable again after subsetting:
> subdf$letters [1] a b c Levels: a b c d e subdf$letters <- factor(subdf$letters) > subdf$letters [1] a b c Levels: a b c
EDIT
From the factor page example:
factor(ff) # drops the levels that do not occur
For dropping levels from all factor columns in a dataframe, you can use:
subdf <- subset(df, numbers <= 3) subdf[] <- lapply(subdf, function(x) if(is.factor(x)) factor(x) else x)
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