hope you fine and well,
i have a drop down list that contains categories list as follows:
<div class='form-group'>
<br/>
<label class='control-label col-md-2 'for='id_date'>Category</label>
<div class='col-md-2' class='form-group' class='col-md-11'>
<select class="form-control " id="sel1" ng-model="category" ng-init="" >
<?php
mysql_connect('localhost', 'root', '');
mysql_select_db('my');
$sql = "SELECT category FROM categories";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result)) {
echo "<option value='" . $row['category'] . "'>" . $row['category'] . "</option>";
} ?>
</select>
</div>
</div>
below this select, i have another select which is to choose element from the category as follows :
<div class='form-group'>
<br/>
label class='control-label col-md-2 ' for='id_date'>element</label>
<div class='col-md-2' class='form-group' class='col-md-11'>
<select class="form-control" id="sel12" ng-model="elemnt" ng-init="" >
<?php
mysql_connect('localhost', 'root', '');
mysql_select_db('my');
$sql = "SELECT element FROM elements where category = ";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result)) {
echo "<option value='" . $row['element'] . "'>" . $row['element'] . "</option>";
} ?>
</select>
</div>
</div>
how i can make the content of the second drop list to be based on the first drop list ?! e.g how i can put the input of the first drop list in the second SQL statement ?!
regards.
You can't do that with only php.
You must use javascript/Jquery and ajax.
Make a php script who load data from a request. After change your first select use ajax function who call your php script with the right value and update the second select.
<select class="form-control " id="sel1" ng-model="category" ng-init="" >
<?php
mysql_connect('localhost', 'root', '');
mysql_select_db('my');
$sql = "SELECT category FROM categories";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result)) {
echo "<option value='" . $row['category'] . "'>" . $row['category'] . "</option>";
} ?>
</select>
Jquery
$("#sel1").change(function(){
$.ajax({
method: "POST",
url: "yourscript.php",
data: {myval : $(this).val()};
})
.done(function( msg ) {
//Here append your result in your second select
});
});
PHP
<?php
if(isset($_POST['myval']))
{
//SQL query where id=myval
echo $result;//result of query
}
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