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Drawing lines on html page

How can we draw a line in html page. I tried using canvas but found that its not working. Maybe browser doesn't support it. Can there be other easier way.

like image 260
sam Avatar asked Nov 24 '10 19:11

sam


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How do I draw a line in HTML canvas?

To draw a line on a canvas, you use the following steps: First, create a new line by calling the beginPath() method. Second, move the drawing cursor to the point (x,y) without drawing a line by calling the moveTo(x, y) . Finally, draw a line from the previous point to the point (x,y) by calling the lineTo(x,y) method.

How do you make a straight line in HTML?

To make a vertical line, use border-left or border-right property. The height property is used to set the height of border (vertical line) element. Position property is used to set the position of vertical line. Example 1: It creates a vertical line using border-left, height and position property.


3 Answers

EDIT: Maybe it is little bit late but here is my new implementation. Hope it's more readable.

function createLineElement(x, y, length, angle) {
    var line = document.createElement("div");
    var styles = 'border: 1px solid black; '
               + 'width: ' + length + 'px; '
               + 'height: 0px; '
               + '-moz-transform: rotate(' + angle + 'rad); '
               + '-webkit-transform: rotate(' + angle + 'rad); '
               + '-o-transform: rotate(' + angle + 'rad); '  
               + '-ms-transform: rotate(' + angle + 'rad); '  
               + 'position: absolute; '
               + 'top: ' + y + 'px; '
               + 'left: ' + x + 'px; ';
    line.setAttribute('style', styles);  
    return line;
}

function createLine(x1, y1, x2, y2) {
    var a = x1 - x2,
        b = y1 - y2,
        c = Math.sqrt(a * a + b * b);

    var sx = (x1 + x2) / 2,
        sy = (y1 + y2) / 2;

    var x = sx - c / 2,
        y = sy;

    var alpha = Math.PI - Math.atan2(-b, a);

    return createLineElement(x, y, c, alpha);
}

document.body.appendChild(createLine(100, 100, 200, 200));

Explanation (as they say "a picture is worth a thousand words"):

Draw line explanation sketch

like image 161
madox2 Avatar answered Sep 26 '22 11:09

madox2


you could define:

<div id="line1" class="line vertical"></div>
<div id="line2" class="line horizontal"></div>

.line {
  position: absolute;
  background-color: #000000;
}

.vertical { 
   width: 1px;
   height: 500px;
}

.horizontal {
   width: 500px;
   height: 1px;
}

#line1 {
   top: 20px;
   left: 50%;
}

#line2 {
   top: 260px;
   left: 25%;
}

/* for added rotation effects */
.forty-five {
   transform: rotate(45deg);
}

if you want to get into diagonal lines you could begin to try some rotation with transform: rotate(45deg); The IE Compatible method of rotating objects is discussed thoroughly here, which is terribly complicated. I do not know the IE compatible way to rotate divs, sorry., but that would work in Safari, Firefox, Chrome, and Opera.

[EDITS]

2014/11/08 - sjc - updated transform rules. Added MozDev links and IE rotation SO links.

like image 30
Metagrapher Avatar answered Sep 28 '22 11:09

Metagrapher


i found myself needing a solution on this so i developped one using "hr" div and some gradient in border-image. Here is a Jsfiddle link to test it and the code below.

<html lang="fr">
<head>
<script>
    window.addEventListener("load",function(){
        function pow2(n){
            return n*n;
        }   

        var p1 = {
            id:"p1",
            x:150,
            y:50
        };
        var p2 = {
            id:"p2",
            x:300,
            y:250
        };
        var select = null;

        function getAngle(){

            var dist = Math.sqrt(pow2(p1.x-p2.x)+pow2(p1.y-p2.y));
            var l = document.getElementById("line");
            var cos = (p2.x-p1.x)/Math.sqrt(pow2(p2.x-p1.x)+pow2(p2.y-p1.y));
            var behind = p1.x < p2.x;
            var higher = p1.y > p2.y;
            l.style.width = (dist*2)+"px";
            l.style.left = (p1.x-dist)+"px";
            l.style.top = (p1.y)+"px";

            l.style.transform = "rotateZ("+(higher?-1:1)*Math.acos(cos)*(180/Math.PI)+"deg)";
        }

        var down = false

        document.addEventListener("mousemove",function(e){
            if(select){
                select.x = e.pageX;
                select.y = e.pageY;
                console.log(p1);
                var p = document.getElementById(select.id);
                p.style.left = (select.x-5)+"px";
                p.style.top = (select.y-5)+"px";
                getAngle();
            }
        });
        document.addEventListener("mouseup",function(e){
            if(!select)
                select = p1;
            else if(select == p1)
                select = p2;
            else 
                select = null;
        });
        document.addEventListener("mousedown",function(e){
            down = true;
        });
    });
</script>
</head>
<body>
<hr id="line" style="
position: absolute;
top: 50px;
left: -100px;
width: 500px;
margin: 0;
-webkit-transform: rotateZ(53.1deg);
border-width: 1px;      border-style: solid;                          
border-image: linear-gradient(to right, #ffffff 0%,#ffffff 49%,#000000 50%,#000000 100%) 1;
"/>
<div id="p1" style="
border-radius: 5px;
width: 10px;
background: #000;
position: absolute;
height: 10px;
top: 45px;
left: 145px;
"></div>
<div id="p2" style="
border-radius: 5px;
width: 10px;
background: #000;
position: absolute;
height: 10px;
top: 245px;
left: 295px;
"></div>
</body>
</html>

hope it helps someone :)

like image 6
Insomniak Dev Avatar answered Sep 28 '22 11:09

Insomniak Dev