Why static_cast
cannot downcast from a virtual base ?
struct A {}; struct B : public virtual A {}; struct C : public virtual A {}; struct D : public B, public C {}; int main() { D d; A& a = d; D* p = static_cast<D*>(&a); //error }
g++ 4.5 says:
error: cannot convert from base ‘A’ to derived type ‘D’ via virtual base ‘A’
The solution is to use dynamic_cast
? but why. What is the rational ?
-- edit --
Very good answers below. No answers detail exactly how sub objects and vtables end up to be ordered though. The following article gives some good examples for gcc:
http://www.phpcompiler.org/articles/virtualinheritance.html#Downcasting
The obvious answer is: because the standard says so. The motivation behind this in the standard is that static_cast
should be close to trivial—at most, a simple addition or subtraction of a constant to the pointer. Where s the downcast to a virtual base would require more complicated code: perhaps even with an additional entry in the vtable somewhere. (It requires something more than constants, since the position of D
relative to A
may change if there is further derivation.) The conversion is obviously doable, since when you call a virtual function on an A*
, and the function is implemented in D
, the compiler must do it, but the additional overhead was considered inappropriate for static_cast
. (Presumably, the only reason for using static_cast
in such cases is optimization, since dynamic_cast
is normally the preferred solution. So when static_cast
is likely to be as expensive as dynamic_cast
anyway, why support it.)
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