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Here's an example:
Double d = (1/3);
System.out.println(d);
This returns 0, not 0.33333... as it should.
Does anyone know?
416
The default value of a numerical data type is 0, so yes. There is positive and negative zero and x == 0 tests for both and will never give you an exception or error.
The doubleValue() method returns the double value represented by this object.
Using the valueOf() method Similarly, the valueOf() method of the Double class (also) accepts a String value as a parameter, trims the excess spaces and returns the double value represented by the string. If the value given is not parsable to double this method throws a NumberFormatException.
If you have ints that you want to divide using floating-point division, you'll have to cast the int to a double:
double d = (double)intValue1 / (double)intValue2
(Actually, only casting intValue2 should be enough to have the intValue1 be casted to double automatically, I believe.)
51
That's because 1 and 3 are treated as integers when you don't specify otherwise, so 1/3 evaluates to the integer 0 which is then cast to the double 0. To fix it, try (1.0/3), or maybe 1D/3 to explicitly state that you're dealing with double values.
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