I have a webView in Android, and I open a html webpage in it. But it's full of links and images, and when I click one of them, it loads in my webview. I want to disable this behaviour, so if I click on a link, don't load it. I've tried this solution and edited a bit for myselft, but not worked. My webviewclient code:
private boolean loaded = false;
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
if(loaded == false){
view.loadUrl(url);
loaded = true;
return true;
}else{
return false;
}
}
My webview implementation and settings.
WebView wv = (WebView) findViewById(R.id.recipeWv);
ourWebViewClient webViewClient = new ourWebViewClient();
webViewClient.shouldOverrideUrlLoading(wv, URLsave);
wv.setWebViewClient(webViewClient);
wv.setFocusableInTouchMode(false);
wv.setFocusable(false);
wv.setClickable(false);
WebSettings settings = wv.getSettings();
settings.setDefaultTextEncodingName("utf-8");
settings.setLoadWithOverviewMode(true);
settings.setBuiltInZoomControls(true);
Example: If the user open in my webview the StackOverflow homepage and clicks on one of the links(like "Questions") then the webview should stay on the StackOverflow homepage.
You should save in a class variable your current url and check if it's the same with the loaded one. When the user clicks on a link the shouldOverrideUrlLoading
is called and check the website.
Something like this:
private String currentUrl;
public ourWebViewClient(String currentUrl) {
this.currentUrl = currentUrl;
}
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
if (url.equals(currentUrl)) {
view.loadUrl(url);
}
return true;
}
Important: don't forget set the WebViewClient
to your WebView
.
ourWebViewClient webViewClient = new ourWebViewClient(urlToLoad);
wv.setWebViewClient(webViewClient);
Implement a WebViewClient and Just return true from this method of WebView Client
webView.setWebViewClient(new WebViewClient(){
public boolean shouldOverrideUrlLoading(WebView view, String url) {
return true;
}
});
If you want to open inner link of a web page in different window then
Don't use
WebView webView;//Your WebView Object
webView.setWebViewClient(new HelpClient());// Comment this line
B'coz setWebViewClient() method is taking care of opening a new page in the same webview. So simple comment this line.
private class HelpClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
if (Uri.parse(url).getHost().equals("www.example.com")) {
// This is my web site, so do not override; let my WebView load the page
return false;
}
// Otherwise, the link is not for a page on my site, so launch another Activity that handles URLs
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
startActivity(intent);
return true;
}
}
Hope this will work.
Even I had been facing the same issue. I solved this issue like below
webView.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
return true;
}
});
With lambda expressions
webView.setOnTouchListener((v, event) -> true);
Note that the method signature changed in API 24.
For APIs earlier than 24 the second parameter is String and that signature is now deprecated.
For APIs 24 and later, the second parameter is WebResourceRequest.
If your app supports both pre and post API 24 and you want to disable all links you can use this:
webView.setWebViewClient(new WebViewClient(){
@Override //for APIs 24 and later
public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request){
return true;
}
@Override //for APIs earlier than 24
public boolean shouldOverrideUrlLoading(WebView view, String url){
return true;
}
});
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