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Does the C# Yield free a lock?

Tags:

yield

c#

locking

I have the following method:

public static IEnumerable<Dictionary<string, object>> GetRowsIter
   (this SqlCeResultSet resultSet)
{
    // Make sure we don't multi thread the database.
    lock (Database)
    {
        if (resultSet.HasRows)
        {
            resultSet.Read();

            do
            {
                var resultList = new Dictionary<string, object>();
                for (int i = 0; i < resultSet.FieldCount; i++)
                {
                    var value = resultSet.GetValue(i);
                    resultList.Add(resultSet.GetName(i), value == DBNull.Value 
                                                                  ? null : value);
                }
                yield return resultList;
            } while (resultSet.Read());
        }
        yield break;
    }

I just added the lock(Database) to try and get rid of some concurancy issues. I am curious though, will the yield return free the lock on Database and then re-lock when it goes for the next iteration? Or will Database remain locked for the entire duration of the iteration?

like image 826
Vaccano Avatar asked Jan 05 '11 19:01

Vaccano


2 Answers

No the yield return will not cause any locks to be freed / unlocked. The lock statement will expand out to a try / finally block and the iterator will not treat this any differently than an explicit try / finally in the iterator method.

The details are a bit more complicated but the basic rules for when a finally block will run inside an iterator method is

  1. When the iterator is suspended and Dispose is called the finally blocks in scope at the point of the suspend will run
  2. When the iterator is running and the code would otherwise trigger a finally the finally block runs.
  3. When the iterator encounters a yield break statement the finally blocks in scope at the point of the yield break will run
like image 183
JaredPar Avatar answered Oct 31 '22 07:10

JaredPar


The lock translates to try/finally (normal C#).

In Iterator blocks (aka yield), "finally" becomes part of the IDisposable.Dispose() implementation of the enumerator. This code is also invoked internally when you consume the last of the data.

"foreach" automatically calls Dispose(), so if you consume with "foreach" (or regular LINQ etc), it will get unlocked.

However, if the caller uses GetEnumerator() directly (very rare) and doesn't read all the data and doesn't call Dispose(), then the lock will not be released.

I would have to check to see if it gets a finaliser; it might get released by GC, but I wouldn't bet money on it.

like image 13
Marc Gravell Avatar answered Oct 31 '22 07:10

Marc Gravell