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I have programmed a method in the following way:
if (something) {
return 1;
}
the rest of the code
It seems to me that the method returns 1 and then execute the rest of the code. Can it be the truth? Doesn't return stops the execution of the code. It it is not, how can I force a method to stop?
ADDED
Here is the code (as requested):
for (int i=availableTime; i>0; i=i-1) {
final int sec = i;
SwingUtilities.invokeLater(new Runnable() {
public void run() {
String lbl = "<html>";
lbl += "</html>";
timeLeftLabel.setText(lbl);
}
});
try {Thread.sleep(1000);} catch (InterruptedException e) {}
parameterFromClientsListener = clientsListener.getValue(userName,parameterToGet);
if (!parameterFromClientsListener.equals("null")) {
output = parameterFromClientsListener;
game.log.fine(userName + " set (by button) " + parameterToGet + " to be equal to " + output + " . [IMPORTANT]");
return output;
}
}
game.log.fine("The partner selection phase is expired.");
// This code is executed if the Submit button was not pressed and the time run out.
if (parameterToGet.equals("partner")) {
tellMyChoice(parameterToGet, this.partnerFromForm, "timer of" + field);
output = this.partnerFromForm;
}
game.log.fine(parameterToGet + " was submitted by timer (not by OK button).");
} else {
output = parameterFromClientsListener;
}
game.log.fine(userName + " set (by timer)" + parameterToGet + " to be equal to " + output + " . [IMPORTANT]");
return output;
}
I run this code two times. In every case I generate a log-file. In both log files I see "set (by button)" statement (which is straight before the return). But the problem is that in the second log file I do see "timer of" statement. Which should not be reached if the "set (by button)" is reached. How can it be? I need to mention that "set (by button)" and "timer of" do not occur anywhere else in my code (they occur only once).
ADDED 3
As you can see from the code I do not have the finally statement.
258
return does end the execution of the method. There is one exception: the finally block. In the following case, 2 would be returned
public int foo() {
try {
return 1;
} finally {
return 2;
}
}
This is not true, the return statement will stop any following code. (With the only exception being that the return statement is in a try{} block that has a finally{} block afterwards.
if(0==0){
return;
}
System.out.println("This will not print.");
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