Like in python I can use slice. Like following
b=[1,2,3,4,5]
a=b[0:3]
Can I do that kind of operation in Lua without a loop. Or Loop is the most efficient way to do that
By creating a new table using the result of table.unpack
(unpack
before Lua 5.2):
for key, value in pairs({table.unpack({1, 2, 3, 4, 5}, 2, 4)}) do
print(key, value)
end
This generates...
1 2
2 3
3 4
(Tested in Lua 5.3.4 and Lua 5.1.5.)
There's no syntax sugar for doing this, so your best bet would be doing it via a function:
function table.slice(tbl, first, last, step)
local sliced = {}
for i = first or 1, last or #tbl, step or 1 do
sliced[#sliced+1] = tbl[i]
end
return sliced
end
local a = {1, 2, 3, 4}
local b = table.slice(a, 2, 3)
print(a[1], a[2], a[3], a[4])
print(b[1], b[2], b[3], b[4])
Keep in mind that I haven't tested this function, but it's more or less what it should look like without checking input.
Edit: I ran it at ideone.
xlua package has table.splice function. (luarocks install xlua)
yourTable = {1,2,3,4}
startIndex = 1; length = 3
removed_items, remainder_items = table.splice(yourTable, startIndex, length)
print(removed_items) -- 4
print(remainder_items) -- 1,2,3
see: https://github.com/torch/xlua/blob/master/init.lua#L640
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