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Does jQuery always return array when selecting element (of course if at least one element exists)? Example:
$('#Myelement')
$('div')
$('tbody')
What if the selector is an ID? What if the selector is an element but has only one occurrence?
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jQuery() Return a collection of matched elements either found in the DOM based on passed argument(s) or created by passing an HTML string.
find() returns an object even when there's no matching child element in the DOM. Save this question.
$ is another, which is just an alias to jQuery . $$ is not provided by jQuery. It's provided by other libraries, such as Mootools or Prototype.
The jQuery inArray() method is used to find a specific value in the given array. If the value found, the method returns the index value, i.e., the position of the item. Otherwise, if the value is not present or not found, the inArray() method returns -1.
The jQuery function always returns a jQuery object (that is based on an array), even if there are no elements that matches the selector.
That way you can always call a method that is supposed to affect the elements found, even if there are no elements that matched. If the jQuery object contains no elements, it will simply do nothing.
If you need to know if a jQuery object contains any elements, you can use the length property.
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Because $([selector]) is like a shortcut of $.find([selector]) which is an element search.
That's anything executed with such jQuery functions may return one or more results, since you're searching rather than "selecting a result".
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