Does Java support default parameter values?

Question

I came across some Java code that had the following structure:

public MyParameterizedFunction(String param1, int param2) {     this(param1, param2, false); }  public MyParameterizedFunction(String param1, int param2, boolean param3) {     //use all three parameters here } 

I know that in C++ I can assign a parameter a default value. For example:

void MyParameterizedFunction(String param1, int param2, bool param3=false); 

Does Java support this kind of syntax? Are there any reasons why this two step syntax is preferable?

Answer 1

No, the structure you found is how Java handles it (that is, with overloading instead of default parameters).

For constructors, See Effective Java: Programming Language Guide's Item 1 tip (Consider static factory methods instead of constructors) if the overloading is getting complicated. For other methods, renaming some cases or using a parameter object can help. This is when you have enough complexity that differentiating is difficult. A definite case is where you have to differentiate using the order of parameters, not just number and type.