In C#, we have 2 modes to build projects : Debug
and Release
, I wonder if Java has the same thing. I am using IntelliJ IDEA as Java IDE and so far I haven't seen anywhere to configure a build mode like in VS IDE.
The Java Debugger, jdb, is a simple command-line debugger for Java classes. It is a demonstration of the Java Platform Debugger Architecture that provides inspection and debugging of a local or remote Java Virtual Machine.
Debugging is the routine process of locating and removing bugs, errors or abnormalities from programs. It's a must have skill for any Java developer because it helps to find subtle bug that are not visible during code reviews or that only happens when a specific condition occurs.
You can now debug your release build application. To find a problem, step through the code (or use Just-In-Time debugging) until you find where the failure occurs, and then determine the incorrect parameters or code.
javac
-g Generate all debugging info
-g:none Generate no debugging info
-g:{lines,vars,source} Generate only some debugging info
You can choose to include debug symbols in the compiled classes (this is the default) or to not do so. There is not much benefit to not doing that. The jar files will be a little smaller, but the performance benefit is minimal (if any). Without these symbols you no longer get line numbers in stack traces. You also have the option to include additional symbols with local variable names (by default there are only source file names and line numbers).
java
-ea[:<packagename>...|:<classname>]
-enableassertions[:<packagename>...|:<classname>]
enable assertions
You can also enable assertions at run-time (default is off), which is sometimes useful during development and testing. This does have a performance impact (if the code in question did indeed make use of assertions, which I think is uncommon).
Regardless of any of these settings, the JVM always allows you to attach a debugger.
What Java does not have is conditional compilation where completely different code would be compiled based on some external setting. The closest you can get is something like public static final boolean DEBUG_BUILD = true;
somewhere in your code and use that in if statements. This will actually make the compiler exclude code that becomes unreachable, but you have to set this constant in the source code.
It is normal practice in Java to release everything is a manner which can be debugged. For some projects requiring obfuscation, they could have a release build, but I have never seen this in 12 years of developing Java.
Things such as assertions and debug messages are usually turned off at runtime for a production instance but can be turned on at any time (even dynamically) if required.
IMHO it is best practice to use the same build in every environment, not just the same source but the same JARs. This gives you the best chance that, if it works in test, it will work in production and if you have a problem in production, you can re-produce it in test.
As so much Java code is written this way, the JIT is very good at optimising dead code which is never called. So much so that IMHO most of the micro-"benchmarks" where Java out performs C++, is when the benchmark doesn't do any thing and the JIT is better at detecting this. IMHO, C++ assumes the developer is smart enough not to write code which doesn't do anything.
You're asking for different kinds of builds to compile in different things I guess. For example to have Debug.WriteLine and Console.WriteLine.
"No, Java doesn't have an exact match for that functionality. You could use aspects, or use an IOC container to inject different implementation classes." stole this from the following question: Conditional Java compilation
(there're other nice answers for you there)
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