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That is, if I have a statement that evaluates multiple conditions, in say a 'or' statement like so..
if(isVeryLikely() || isSomewhatLikely() || isHardlyLikely()) { ... } In the case that isVeryLikely() returns true at runtime, will isSomewhatLikely() and isHardlyLikely() execute? How about if instead of methods they were static booleans?
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At run time, the left-hand operand expression is evaluated first; if the result has type Boolean, it is subjected to unboxing conversion (§5.1. 8). If the resulting value is true, the value of the conditional-or expression is true and the right-hand operand expression is not evaluated.
Order of operand evaluation in Java. In Java, the operands of an operator are always evaluated left-to-right.
The if statement will evaluate whatever code you put in it that returns a boolean value, and if the evaluation returns true, you enter the first block. Else (if the value is not true, it will be false, because a boolean can either be true or false) it will enter the - yep, you guessed it - the else {} block.
These operators include equality ( == ) and inequality ( != ). The former operator returns true when both operands are equal; the latter operator returns true when both operands are unequal.
The || and && operators are short-circuiting.
true || willNeverExecute(); false && willNeverExecute(); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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