Does calling clone() on an array also clone its contents?

Question

If I invoke clone() method on array of Objects of type A, how will it clone its elements? Will the copy be referencing to the same objects? Or will it call (element of type A).clone() for each of them?

Answer 1

clone() creates a shallow copy. Which means the elements will not be cloned. (What if they didn't implement Cloneable?)

You may want to use Arrays.copyOf(..) for copying arrays instead of clone() (though cloning is fine for arrays, unlike for anything else)

If you want deep cloning, check this answer

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A little example to illustrate the shallowness of clone() even if the elements are Cloneable:

ArrayList[] array = new ArrayList[] {new ArrayList(), new ArrayList()}; ArrayList[] clone = array.clone(); for (int i = 0; i < clone.length; i ++) {     System.out.println(System.identityHashCode(array[i]));     System.out.println(System.identityHashCode(clone[i]));     System.out.println(System.identityHashCode(array[i].clone()));     System.out.println("-----"); } 

Prints:

4384790   4384790 9634993   -----   1641745   1641745   11077203   -----   

Answer 2

If I invoke clone() method on array of Objects of type A, how will it clone its elements?

The elements of the array will not be cloned.

Will the copy be referencing to the same objects?

Yes.

Or will it call (element of type A).clone() for each of them?

No, it will not call clone() on any of the elements.