I know that logical operators do short-circuit checking. That is, if there is a statement like A && B && C, then if A is false, B and C are not evaluated. But is this also true in cases where B and C are function calls?
For example, the return statement in this code:
bool areIdentical(struct node * root1, struct node *root2)
{
/* base cases */
if(root1 == NULL && root2 == NULL)
return true;
if(root1 == NULL || root2 == NULL)
return false;
/* Check if the data of both roots is same and data of left and right
subtrees are also same */
return (root1->data == root2->data && //I am talking about this statement
areIdentical(root1->left, root2->left) &&
areIdentical(root1->right, root2->right) );
}
Yes, the functions are not called if root1->data == root2->data is false.
Simple check is to do this:
#include <unistd.h>
#include <stdlib.h>
int main(void)
{
write(1, "z", 1);
if ((1 == 0) && write(1, "a", 1) && write(1, "b", 1))
{
write(1, "c", 1);
}
write(1, "d", 1);
return (EXIT_SUCCESS);
}
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