document.getElementById("remember").visibility = "hidden"; not working on a checkbox

Question

I cannot get the visibility or display properties to work.

Here is the HTML footer:

<div id="footer">
  &copy; 
  <strong id="foot" onmouseover="showData();" onmouseout = "hideData()">
    Exquisite Taste 2012
  </strong>
  <input type='checkbox' id="remember" onclick='editCookie()' style="visibility:hidden;" />
</div>

Here is the .js function with the visibility part not working:

function showData()
{


  document.getElementById("remember").visiblity="visible";


  document.getElementById("foot").innerHTML = getDate() + "  " + getTime();

  if(cookieValue())
  {
    document.getElementById("remember").checked = true;
  }
}

That one line doesn't seem to do anything:

document.getElementById("remember").visiblity="visible";

Answer 1

There are two problems in your code:

• The property is called visibility and not visiblity.
• It is not a property of the element itself but of its .style property.

It's easy to fix. Simple replace this:

document.getElementById("remember").visiblity

with this:

document.getElementById("remember").style.visibility

Answer 2

This is the job for style property:

document.getElementById("remember").style.visibility = "visible";