Do something when exactly one option is non-empty

Question

I want to compute something if exactly one of two options is non-empty. Obviously this could be done by a pattern match, but is there some better way?

(o1, o2) match {
  case (Some(o), None) => Some(compute(o))
  case (None, Some(o)) => Some(compute(o))
  case _ => None
}

Answer 1

You could do something like this:

if (o1.isEmpty ^ o2.isEmpty)
  List(o1,o2).flatMap(_.map(x=>Some(compute(x)))).head
else
  None

But pattern matching is probably the better way to go.