Do I need to free the strtok resulting string?

Question

Or rather, how does strtok produce the string to which it's return value points? Does it allocate memory dynamically? I am asking because I am not sure if I need to free the token in the following code:

The STANDARD_INPUT variables is for exit procedure in case I run out of memory for allocation and the string is the tested subject.

int ValidTotal(STANDARD_INPUT, char *str) {     char *cutout = NULL, *temp, delim = '#';     int i = 0; //Checks the number of ladders in a string, 3 is the required number     temp = (char*)calloc(strlen(str),sizeof(char));     if(NULL == temp)         Pexit(STANDARD_C); //Exit function, frees the memory given in STANDARD_INPUT(STANDARD_C is defined as the names given in STANDARD_INPUT)     strcpy(temp,str);//Do not want to touch the actual string, so copying it     cutout = strtok(temp,&delim);//Here is the lynchpin -      while(NULL != cutout)     {         if(cutout[strlen(cutout) - 1] == '_')             cutout[strlen(cutout) - 1] = '\0'; \\cutout the _ at the end of a token         if(Valid(cutout,i++) == INVALID) //Checks validity for substring, INVALID is -1             return INVALID;         cutout = strtok(NULL,&delim);         strcpy(cutout,cutout + 1); //cutout the _ at the beginning of a token     }     free(temp); return VALID; // VALID is 1 } 

Answer 1

strtok manipulates the string you pass in and returns a pointer to it, so no memory is allocated.

Please consider using strsep or at least strtok_r to save you some headaches later.