Django template tag: How to send next_page in {url auth_logout}?

Question

I have an urls.py with this line:

url(r'^logout/$', 'django.contrib.auth.views.logout', name="auth_logout"),

In my template tag i have this line:

<a href="{% url auth_logout %}">Logout</a>

Now, I would like to add the next_page param to the url templatetag, but I can't get it to work. I have tried this:

{% url auth_logout request.path %}"

...and this:

{% url auth_logout request,request.path %}

But none of them works. How can I provide the function with the optional next_page paramter usinging the url templatetag?

Thanks!

Answer 1

For what it's worth, I use this:

<a href="{% url auth_logout %}?next=/">Logout</a>

Answer 2

Two things:

1. django.contrib.auth.views.logout() takes an optional next_page which you are not providing
2. url templatetag has comma-separated arguments

So, first modify your url to accept next_page Your URLConf needs modification to pass in the next page, something like this for a hard-coded redirect:

url(r'^logout/$', 'django.contrib.auth.views.logout', {'next_page': '/'}, name='auth_logout'), 

and one parameterized result:

url(r'^logout/(?P<next_page>.*)/$', 'django.contrib.auth.views.logout', name='auth_logout_next'), 

And then modify your template to pass in the next_page

<a href="{% url auth_logout_next /some/location %}">Logout</a>

• Docs on logout
• Docs on url templatetag