Django template, if tag based on current URL value

Question

I want to be able to do an if tag based on the current URL value.

for example, if the current page's url is accounts/login/ then don't show a link, without passing a variable from the view.

I am not sure how I can write an {% if %} tag for this, is it possible?

Answer 1

You can also do this for dynamic urls using:

{% url 'show_user_page' user=user as the_url %} {% if request.get_full_path == the_url %}something{% endif %} 

where your urls.py contains something like:

(r'^myapp/user/(?P<user>\d+)/$', 'show_user_page'), 

I know this because I just spent ages drafting a stackoverflow question, when I found the answer in the docs.

I'd say even in simple cases this might be the better approach, because it is more loosely coupled.

Answer 2

If you pass the "request" object to your template, then you are able to use this:

{% if request.get_full_path == "/account/login/" %}