Django nested 'with' and 'block' tag

Question

I have base.html template like this:

<p>{% block a %}{% endblock %}</p>
<p>{% block b %}{% endblock %}</p>

And index.html template:

{% extends "base.html" %}

{% with description="foo" %}
  {% block a %}{{ description }}{% endblock %}
  {% block b %}{{ description }}{% endblock %}
{% endwith %}

But the result becomes:

<p></p>
<p></p>

Instead of:

<p>foo</p>
<p>foo</p>

Is there any workaround for this?

Answer 1

Not in the way you'd like it to, in inherited templates django looks for code inside of blocks which means it won't recognize the existence of your with block outside of this. so your only option is to include the with inside each block

{% block a %}    
    {% with description="foo" %}
        {{ description }}
    {% endwith %}    
{% endblock %}

Although for a single call it isn't worth using the with, the only other option is to pass description through the context

Answer 2

UPDATE: It doesn't work as I expected for my particular case. See comments.

After reading Sayse's answer and understanding better how blocks work, I've come with this solution:

base.html:

{% block wrapping_block %}
    {% block a %}
    {% endblock %}

    {% block b %}
    {% endblock %}
{% endblock %} 

index.html:

{% extends "base.html" %}

{% block wrapping_block %}
    {% with description='foo' %}
        {% block a %}
            {{ description }}
        {% endblock %}

        {% block b %}
            {{ description }}
        {% endblock %}
    {% endwith %}
{% endblock %}