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In my models.py, I have two classes, ChoiceList and SampleModel as below
class ChoiceList(models.Model):
choice=models.CharField(max_length=15)
class SampleModel(models.Model):
CHOICELIST=ChoiceList.objects.all()
name=models.CharField(max_length=15)
your_choice=models.CharField(max_length=15,choices=ChoiceList)
I need to add your_choice field data only from ChoiceList instances. Can I add data in that way ?
When I doing this way, I got error as django.db.utils.OperationalError: no such table: rest_api_ChoiceList
Can anyone solve the problem ?
390
To create a new instance of a model, instantiate it like any other Python class: class Model (**kwargs) The keyword arguments are the names of the fields you've defined on your model. Note that instantiating a model in no way touches your database; for that, you need to save() .
To answer your question, with the new migration introduced in Django 1.7, in order to add a new field to a model you can simply add that field to your model and initialize migrations with ./manage.py makemigrations and then run ./manage.py migrate and the new field will be added to your DB. Save this answer.
The __str__ method just tells Django what to print when it needs to print out an instance of the any model.
This field can be useful as a primary key of an object if that object extends another object in some way. For example – a model Car has one-to-one relationship with a model Vehicle, i.e. a car is a vehicle. One-to-one relations are defined using OneToOneField field of django.
you should use ForeignKey()
your_choice=models.ForeignKey(ChoiceList,on_delete=models.CASCADE)
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