Django form __init__() got multiple values for keyword argument

Question

Hello, I'm trying to use a modified __init__ form method, but I am encountering the following error:

TypeError __init__() got multiple values for keyword argument 'vUserProfile' 

I need to pass UserProfile to my form, to get to dbname field, and I think this is a solution (my form code):

class ClienteForm(ModelForm): class Meta:     model = Cliente  def __init__(self, vUserProfile, *args, **kwargs):     super(ClienteForm, self).__init__(*args, **kwargs)     self.fields["idcidade"].queryset = Cidade.objects.using(vUserProfile.dbname).all() 

Calls to constructor ClienteForm() without POST are successful and show me the correct form. But when the form is submitted and the constructor is called with POST, I get the previously described error.

Answer 1

You've changed the signature of the form's __init__ method so that vUserProfile is the first argument. But here:

formPessoa = ClienteForm(request.POST, instance=cliente, vUserProfile=profile) 

you pass request.POST as the first argument - except that this will be interpreted as vUserProfile. And then you also try to pass vUserProfile as a keyword arg.

Really, you should avoid changing the method signature, and just get the new data from kwargs:

def __init__(self, *args, **kwargs):     vUserProfile = kwargs.pop('vUserProfile', None) 

Answer 2

For the help of those others who Google to here: the error comes from init picking up the argument from both a positional argument and the default argument. Daniel Roseman's is accurate for the question as asked.

This can be either:

1. You put the argument by position and then by keyword:

   class C():   def __init__(self, arg): ...  x = C(1, arg=2)   # you passed arg twice!   

2. You forgot to put self as the first argument:

   class C():    def __init__(arg):  ...  x = C(arg=1)   # but a position argument (for self) is automatically                 # added by __new__()!